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It will be come a terminal node. Normally we call terminal nodes leaf nodes because a leaf has no branches other than its parent.

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Q: When we insert a new node in a binary search tree will it become an internal node or terminal node?
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You use OLE Object fields to insert documents (Word, PDF, bitmap images, etc) into records. The OLE Object itself is actually a binary data field and the only way to compare any two OLE Objects is to compare the binary data itself. This makes no sense because we normally compare documents by type, size, author, title, creation date, last modified date, and so on, we don't compare their physical representations (the binary data itself). If we want to sort documents, we must extract the properties we wish to sort by and insert them as separate fields in our records, and use those fields as our index/sort keys. Sometimes we really do need to use binary data as a sort key, but we cannot use an OLE Object to store that data because OLE Objects cannot be used as sort keys. Instead, we must use the built-in binary data field which can be indexed and sorted. Binary data fields can be fixed-length (binary) or variable length (varbinary). Note that OLE Objects are variable length with a theoretical limit of 1 GB, which is yet another reason why they are unsuitable for indexing. The fixed-length binary field has an upper limit of 510 bytes, making it ideal for indexing and sorting small amounts of binary data. Unfortunately, the built-in binary data fields cannot be created using the table designer for no practical reason other than Microsoft decreed that you couldn't. Instead you must use DDL or VBA/DAO. Using DDL, the following will create a binary and a varbinary field. For completeness, I've also included an OLE Object field: CREATE TABLE tblBinTestSQL ( Id counter NOT NULL PRIMARY KEY, VarbinaryColumn varbinary(100) NULL, BinaryColumn binary(100) NULL, OLEColumn Longbinary NULL ); Here's the VBA/DAO method of achieving the same thing: Public Sub CreateBinaryColumns() Dim td As DAO.TableDef Dim db As DAO.Database Dim fd As Field Set db = CurrentDb Set td = db.CreateTableDef("tblBinTestDAO") Set fd = td.CreateField("ID", DataTypeEnum.dbLong) fd.Attributes = fd.Attributes Or dbAutoIncrField td.Fields.Append fd Set fd = td.CreateField("BinaryColumn", DataTypeEnum.dbBinary, 100) fd.Attributes = fd.Attributes Or dbFixedField td.Fields.Append fd Set fd = td.CreateField("VarbinaryColumn", DataTypeEnum.dbBinary, 100) td.Fields.Append fd Set fd = td.CreateField("OLEColumn", DataTypeEnum.dbLongBinary) td.Fields.Append fd db.TableDefs.Append td End Sub Once you have at least one table with a binary or varbinary field, you can simply copy that field to other tables. You can also modify the properties of those fields in table designer; you just can't use table designer to create those fields.


C plus plus program to insert an element using binary tree?

The algorithm for inserting into a binary tree is fairly straightforward. Start by passing the element to the root node of the tree. If there is no root, the new element becomes the root and you're done. Whenever a node receives a new element, it compares the element's value with its own value. If the new element is lower in value, pass the element to the left node otherwise pass it to the right node. If there is no node in that position, the new element becomes that node. In this way, the node's themselves decide where new elements are placed. In order to achieve this you need a node that encapsulates some data. Typically the data is a template parameter but for the sake of simplicity let us assume the data is an unsigned integer. We'll also need pointers to the left and right nodes. We'll use the default constructor to initialise the data and pointers. we'll also need an insertion method. Thus our node class looks like this: class node { private: node* left; node* right; unsigned data; public: node(unsigned value): left(NULL), right(NULL), data(value) {} void insert(unsigned value); }; The insert method will be implemented as follows: void node::insert(unsigned value) { if (value<data) { if (left) left->insert(value); else left = new node(value); } else { if (right) right->insert(value); else right = new node(value); } } That's all there is to it. All you need now is a pointer to the root which will initially be NULL. When you come to insert a value and the root is NULL, create a new node and assign it to the root pointer, otherwise call root->insert(value); and let the tree sort itself out.

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