IN hyderabad near koti
To calculate the current you need to take theWatt rating of your welder and divide this by the voltage youhave setthe machine at- this gives the amperage. So for a 1440 watt welder running at 12v the current would be: 1440 watt/ 12v = 120 Amps
0.1764 amps
The supply won't have to work as hard. It is perfectly acceptable, for example, to use a 1A, 12v supply to supply a 12v, .5A load. The current rating indicates the ability of the supply to dissipate heat caused by the current flowing. If the load current is above the power supply current rating, the power supply will overheat.
That would also depend on battery chemistry.
V=i*r=2*6=12v
The same as a 12V relay circuit, except it only needs 6V instead of 12V.
Probably...The 6V 40A relay figures out as 240Watts...The same relay at 12V 30A figures out as 360Watts.
No, you cannot use a 50 amp automotive relay with a 12V DC coil to control 12V AC 500 watt halogen lighting. Automotive relays are designed to work with DC power, not AC power. Additionally, the amp rating of the relay refers to its capacity for DC load, not AC load. You should use a relay specifically designed for AC applications with the appropriate voltage and current ratings.
12v , 7Ah means its the capicity of Battery , if load current is 1 amp then battery runs for 7 hrs. AH = Ampere* Current. 12v, 7ah 20hrs its shows load current is 7/20 amp.
This will be because someone has changed the wiring configuration - The electric window relay should be energised via a switched 12v (either straight from the ignition switch or from ignition relay) to switch a bigger current to power all the windows. In this case someone has removed the relay coil 12v feed from the switched source and connected it to a permanant source (straight from the battery and not via any switches.) -Daz Ellerington.
the answer is yes as long as the device works on dc current and not ac current if you tell me what the device is i might be able to help further
Yes, you need to match the Voltage, the current (A) need to be the same or higher.
obviously you need a bigger fuse and a bigger relay
No, the new adapter will not be able to safely supply enough current.
The power dissipated by a circuit with a voltage of 12V and a current of 3A is 36W. Watts is Volts times Amps.
The output voltage of 12V 5W solar panel is 12V. The current is 0,41667A. These values are normaly calculated with 1000W/m2 of solar radiation.
1500W@12V means a current of 125A, that's quite a lot. You have to check what's the max discharge current allowed for your 12V source. There's no general answer.