The question is nonsense. WHICH bond angle? There are many of them in a molecule the size of estradiol.
The value of the bond angle in XeF2 is 180 degrees.
90 degrees is the value of the smallest bond angle in IF4.
The lone pair - OH bond repulsion in water is greater than the OH bond- OH bond repulsion. In methane all of the bonds are the same so it has perfect tetrahedral symmetry. This is VSEPR theory
The bond length is equal to the linear distance between the nuclei of the bonding atoms. The bond angle is equal to the angle between any two consecutive bonds in a molecule or ion. Bond angles of molecules and ions are usually determined by using the VSEPR theory.
The lone pair - OH bond repulsion in water is greater than the OH bond- OH bond repulsion. In methane all of the bonds are the same so it has perfect tetrahedral symmetry. This is VSEPR theory
in water there are two bond pairs and two lone pairs where as in CH4 there are are four bond pairs nad no lone pair. in ch4 there is only bond pair to bond pair repulsion but in water there are three types of repulsions, lone to lone (greatest repulsion), lone to bond ( lesser repulsion ) and bond to bond ( the least repulsion) , therefore due to the presence of two lone pairs in water the bond pairs are repelled with greater force and they get compressed, reducing the ideal bond angle from 109.5 to 104.5 on the other hand, ch4 has only bond pairs and they dont repel each other that strongly so its angle is greater n its 109.5..
Increases
Bond angle is 109.5 degrees.It is equal in every bond
NH4+ is tetrahedral, with bond angle of 109.5o
the f-p-f bond angle is 120the cl -p-cl bond angle is 180and the f - p - cl bond angle is 90
Bond Angle (:
The bond angle for H2S is 92.1­°.
Tetrahedral
It is Polar
If by "then" you meant "than", then the answer could be a straight angle.
The water molecule's bond angle is about 104.45 degrees.