This is an odd question. Hybridisation is a "trick" used in valence bond theory to form orbitals that have the correct geometry and optimise orbital overlap. In principle you can mathematically hybridise orbitals of suitable symmetry. Typically in valence bond theory you see s and p orbitals hybridised to sp, sp2 and sp3 hybrids and , s, p and d orbitals forming sp3d and sp3d2
4s-orbital will be filled prior to 3d-orbital.ORBITALnl(n+l)4s404+0 = 43d323+2 = 5Since 4s-orbital has least value of (n+l), therefore ,it will occupy electrons before3d-orbital.The order of increasing of energy of orbitals can be calc. from(n+l) rule or 'Bohr bury rule' According to this rule, the value of n+l is the energy of the orbital and such on orbital will be filled up first. e.g. 4s orbital having lower value of(n+l) has lower energy than 3d orbital and hence 4s orbital is filled up first. For 4s orbital, n+l=4+0=4 For 3d orbital, n+l=3+2=5,therefore 4s orbital will be filled first.
During electron capture, an electron and proton combine and are converted to a neutron.
During pollination, like when bees carry pollen from one to another, that allows them to combine
methanol. CH2O > The hydride forms a bond with the anti bonding orbital of the carbonyl carbon and oygen pi bond, which breaks, THe filled antibond orbital, is then a sigma bond, and occured during reduction via a HYDRIDE acting as a nucleophile. THIS leaves CH3O- A methoxide, which is extremely reactive, and upon work up, forms an alcohol. METHANOL.
Cells combine to create a baby through a process called fertilization. During sexual reproduction, a sperm cell from a male and an egg cell from a female join together in a process called fertilization. This forms a zygote, which is the first cell of a new organism. The zygote then undergoes cell division and development to eventually form a baby.
Electrons are located in all the shells before the last shell but when doing equations and working things out, you only refer to the last shell. This is because the shells before the last shell are all full (the first one has only 2 electrons but the rest have 8) and only the outer shell electrons, known as valance electrons, react with other substances.
4s-orbital will be filled prior to 3d-orbital.ORBITALnl(n+l)4s404+0 = 43d323+2 = 5Since 4s-orbital has least value of (n+l), therefore ,it will occupy electrons before3d-orbital.The order of increasing of energy of orbitals can be calc. from(n+l) rule or 'Bohr bury rule' According to this rule, the value of n+l is the energy of the orbital and such on orbital will be filled up first. e.g. 4s orbital having lower value of(n+l) has lower energy than 3d orbital and hence 4s orbital is filled up first. For 4s orbital, n+l=4+0=4 For 3d orbital, n+l=3+2=5,therefore 4s orbital will be filled first.
Yes
The two atoms that combine are a metal atom and an oxygen atom.
because the behr cannot respond quick Edited answer: During hybridization additive gene action from the two parents result in heterosis which ultimately increases food production in crop plants.
They actually do combine during electrolysis of aqueous Sodium Chloride
1. Less than the octet Elements B and Be 2. More than the octet Elements from Period 3 and beyond. Since these elements have d orbitals (n=3, therefore they contain an s,p and d), the d orbital can accommodate extra electrons during bonding. 3. Free radicals Molecules with at least one unpaired electron.
respiration
Lavoisier.
During electron capture, an electron and proton combine and are converted to a neutron.
Methylene blue is an electron acceptor during the hybridization process. It is the process of combining different varieties of organisms to create a hybrid.
Stoichiometry is the study of the relative proportions of elements that combine during chemical reactions.