The 8086/8088 processor is called a 16 bit processor because its basic architecture is 16 bits wide. Its registers and accumulator are 16 bits wide, and the primary data it manipulates without extra work is 16 bits wide.
The 8085 is known as an 8-bit microprocessor because its arithmetic/logic unit is 8-bits in size, it has an 8-bit accumulator, its primary data path is 8-bits in size, and most of its general registers are 8-bits in size. Do not be confused by the fact that some things are 16-bits in size, such as the address bus, and the BC, DE, HL register pairs, as well as the PC and SP registers, and certain 16-bit operations that can be performed; the 8085 is an 8-bit computer.
The 8085 is called an 8-bit processor because the integers and memory addresses it could handle were 8 bits in width. The 8086 could handle 16-bit integers and memory addresses.
Because the bus size is 8 bit..
There are multiple answers to this..
One may say that the processor is capable of processing 8 bits of data at a time so its an 8 bit processor.
Because the accumulator and primary data path are 16 bits in size.
8086 is a 16bit processor.
No. The 8086 has instructions not present in the 8085. The 8086 was marketed as "source compatible" with the 8085, meaning that there was a translator program which could convert assembly language code for the 8085 into assembly language code for the 8086. However, this does not mean that the compiled 8086 assembly code would then run on an 8085; among other things, the 8086 was a true 16-bit processor, as opposed to the 8085 which was an 8-bit processor that supported a few 16-bit operations.
we can measure the water level
Because the accumulator and primary data path is 16 bits. Also, that how Intel designed it.
The 8085 microprocessor was an enhanced version of the 8080, primarily running on a single +5V power supply, hence the designation 8085.The 8086 microprocessor was an enhanced version of the 8085, primarily running as a 16 bit processor, hence the designation 8086.The 8088 microprocessor (part of the 8086/8088 family) was a version of the 8086 that run on an 8 bit bus, hence the designation 8088.
The most significant difference between the Intel 8085 and 8086 microprocessors is that the 8085 is an 8-bit system and the 8086 is a 16-bit system. This difference allows the 8086 system to have a much larger set of operational instructions and can make calculations to more significant places. Note: the 8085 processor does have two 16-bit registers. The pointer and the program counter.
Somewhat after the 8086, which was somewhat after the 8085. The 8086 was developed between mid 1976 and early 1978, while the 8088 was developed in 1979.
it primarily running as a 16 bit processor..so it is so called as 8086
The 8085 and 8086/8088 operate on 5 volts.
Its 16bit microprocessor,and-> the 8086 has a 16bit databus 20bit address bus-> the intel 8086,is designed to operate in two modes namely(1) minimum mode(2) maximum mode
a number (1) because 8085+1=8086
The 8085 is an 8-bit microprocessor. Even though there are some 16-bit registers (BC, DE, HL, SP, PC), with some 16-bit operations that can be performed on them, and a 16-bit address bus, the accumulator (A), the arithmetic logic unit (ALU), and the data bus are 8-bits in size, making the 8085 an 8-bit computer.