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Why a class should extends a class first and should implements a interface second?
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How do you code to inherit from an interface in java?
We have been using references to the term "Implementing an Interface" throughout the preceding chapters and we havent yet actually dug deep into this topic. As you might remember, an Interface is nothing but a contract as to how a class should behave. It just declares the behavior as empty methods and the implementing class actually writes the code that will determine the behavior. When you implement an interface, you're agreeing to adhere to the contract defined in the interface. That means you're agreeing to provide legal implementations for every method defined in the interface, and that anyone who knows what the interface methods look like can rest assured that they can invoke those methods on an instance of your implementing class. (Thy need not bother much about how you have implemented it. All they bother about is whether a method of the name mentioned in the interface is available or not) Now, you might stop me and ask, what if I implement an interface and opt not to write code for a method that I am supposed to? The answer is simple. The compiler wouldn't let you do that. You cannot successfully implement an interface without providing method implementation for all the methods declared inside the interface. This is how the java system ensures that when someone knows a certain method name in an interface and has an instance of a class that implements it, can actually call that method without fear that the method isn't implemented inside the class. Assuming an interface, Convertible, with two methods: openHood(), and setOpenHoodFactor(), the following class will compile: public class Ball implements Convertible { // Keyword 'implements' public void openHood() { } public void setOpenHoodFactor(int bf) { } } Ok, I know what you are thinking now. "This has got to be the worst implementation class that you have seen". Though it compiles and runs as well, it is actually doing nothing… the interface contract guarantees that the class implementing it will have a method of a particular name but it never guaranteed a good implementation. In other words, the compiler does not bother whether you have code inside your method or not. All it cares is if you have methods of the matching names as in the interface. That's all… Implementation classes must adhere to the same rules for method implementation as a class extending an abstract class. In order to be a legal implementation class, a nonabstract implementation class must do the following: • Provide concrete (nonabstract) implementations for all methods from the declared interface. • Follow all the rules for legal overrides. • Declare no checked exceptions on implementation methods other than those declared by the interface method, or subclasses of those declared by the interface method. • Maintain the signature of the interface method, and maintain the same return type (or a subtype). • It does not have to declare the exceptions declared in the interface method declaration.
What is a predefined interface in java?
An interface is a collection of methods that must be implemented by the implementing class.An interface defines a contract regarding what a class must do, without saying anything about how the class will do it.Interface can contain declaration of methods and variables.implementing class must define all the methods declared in the interfaceIf a class implements an interface and does not implement all the methods then class itself must be declared as abstractVariables in interface automatically become static and final variableof the implementing classMembers of interface are implicitly public, so need not be declared as public.An interface must be implemented in class.
What should a kitchen have?
A Cook, kitcken implements and utensils, instruments such as ovens etc also
Why use interfaces in Java?
an Interface is nothing but a contract as to how a class should behave. It just declares the behavior as empty methods and the implementing class actually writes the code that will determine the behavior. When you implement an interface, you're agreeing to adhere to the contract defined in the interface. That means you're agreeing to provide legal implementations for every method defined in the interface, and that anyone who knows what the interface methods look like can rest assured that they can invoke those methods on an instance of your implementing class. (Thy need not bother much about how you have implemented it. All they bother about is whether a method of the name mentioned in the interface is available or not) Now, you might stop me and ask, what if I implement an interface and opt not to write code for a method that I am supposed to? The answer is simple. The compiler wouldn't let you do that. You cannot successfully implement an interface without providing method implementation for all the methods declared inside the interface. This is how the java system ensures that when someone knows a certain method name in an interface and has an instance of a class that implements it, can actually call that method without fear that the method isnt implemented inside the class. Assuming an interface, Convertible, with two methods: openHood(), and setOpenHoodFactor(), the following class will compile: public class Ball implements Convertible { // Keyword 'implements' public void openHood() { } public void setOpenHoodFactor(int bf) { } } Ok, I know what you are thinking now. "This has got to be the worst implementation class that you have seen". Though it compiles and runs as well, it is actually doing nothing… the interface contract guarantees that the class implementing it will have a method of a particular name but it never guaranteed a good implementation. In other words, the compiler does not bother whether you have code inside your method or not. All it cares is if you have methods of the matching names as in the interface. That's all… Implementation classes must adhere to the same rules for method implementation as a class extending an abstract class. In order to be a legal implementation class, a nonabstract implementation class must do the following: • Provide concrete (nonabstract) implementations for all methods from the declared interface. • Follow all the rules for legal overrides. • Declare no checked exceptions on implementation methods other than those declared by the interface method, or subclasses of those declared by the interface method. • Maintain the signature of the interface method, and maintain the same return type (or a subtype). • It does not have to declare the exceptions declared in the interface method declaration
What is an interface and how will you go about implementing an interface?
an Interface is nothing but a contract as to how a class should behave. It just declares the behavior as empty methods and the implementing class actually writes the code that will determine the behavior. When you implement an interface, you're agreeing to adhere to the contract defined in the interface. That means you're agreeing to provide legal implementations for every method defined in the interface, and that anyone who knows what the interface methods look like can rest assured that they can invoke those methods on an instance of your implementing class. (Thy need not bother much about how you have implemented it. All they bother about is whether a method of the name mentioned in the interface is available or not) Now, you might stop me and ask, what if I implement an interface and opt not to write code for a method that I am supposed to? The answer is simple. The compiler wouldn't let you do that. You cannot successfully implement an interface without providing method implementation for all the methods declared inside the interface. This is how the java system ensures that when someone knows a certain method name in an interface and has an instance of a class that implements it, can actually call that method without fear that the method isn't implemented inside the class. Assuming an interface, Convertible, with two methods: openHood(), and setOpenHoodFactor(), the following class will compile: public class Ball implements Convertible { // Keyword 'implements' public void openHood() { } public void setOpenHoodFactor(int bf) { } } Ok, I know what you are thinking now. "This has got to be the worst implementation class that you have seen". Though it compiles and runs as well, it is actually doing nothing… the interface contract guarantees that the class implementing it will have a method of a particular name but it never guaranteed a good implementation. In other words, the compiler does not bother whether you have code inside your method or not. All it cares is if you have methods of the matching names as in the interface. That's all… Implementation classes must adhere to the same rules for method implementation as a class extending an abstract class. In order to be a legal implementation class, a nonabstract implementation class must do the following: • Provide concrete (nonabstract) implementations for all methods from the declared interface. • Follow all the rules for legal overrides. • Declare no checked exceptions on implementation methods other than those declared by the interface method, or subclasses of those declared by the interface method. • Maintain the signature of the interface method, and maintain the same return type (or a subtype). • It does not have to declare the exceptions declared in the interface method declaration.
When do you give preference to abstract classs and interface?
Abstract class provides a way of "being a [something like me]", or inheritance interface provides a set of functionality (contract) as "behaving". Abstract class provides the single inheritance and perhaps some default implementation, while interface may be implemented by different classes that have nothing to do one and other except the common interface implementation. The preference I would start with: Ask yourself that an object should be "Is a something or behave like something". If your answer is "Is a", then abstract class is more likely your good choice. But if your answer is behave like, does not need to Is a, then the interface is the way to go.
What is Microsoft Six Rules Standardfor User Interface testing?
User Interface Testing come under GUI (Graphic User Interface) testing. GUI is a functional testing. Six Rules for Microsoft user interface testings are:- * Controls should be clear and visible * Controls should be aligned properly * Controls should not be overlapped * Initial letter should be in capital letters * Making sure that "Ok" & "Cancel" buttons exists. * Making sure that "System Menu" exists.
Router have a mac id on its interface yes or no?
it should be on back of router!
How can mallet finger be prevented?
Caution should be used when playing ball sports or using knives or other sharp implements.
What is the difference between cloning and seriliazation in java?
Cloning is the act of creating a new copy of an object. The new object should store all the same information as the original, but the physical data should be different.Serialization is the act of turning an Object into an array of bytes which represent the data. This is used mainly for storing objects to disk. An Object which implements the Serializable interface can be used by ObjectInputStream and ObjectOutputStream to easily hook into the java.io package.
Which command turns on a router interface?
While in the interface mode your prompt should look like this:RouterName(config-if)#Then type the command:RouterName(config-if)# no shutdown
What venous sinus extends from the superior cistern to the confluence of the sinuses?
Should be the straight sinus i think
