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k2cr2o7+FeSO4+H2SO4 --> Cr2(SO4)3+Fe2(SO4)3+K2SO4+H2O
The reaction between NaOH and H2SO4 is highly exothermic, meaning it releases heat. When the solutions are mixed in the conical flask and shaken during titration, this reaction occurs and produces a significant amount of heat. Additionally, the presence of phenolphthalein might contribute to the sensation of heat as it can change color when exposed to heat or pH changes, indicating the progress of the reaction.
HI + H2SO4 = HIO- + H2SO3-
H2SO4 is a highly concentrated acid.
An example is:2 KOH + H2SO4 = K2SO4 + 2 H2O
Methyl orange
(25.00ml H2SO4)(H2SO4 M) = (22.65ml NaOH)(0.550M) = 0.4983M H2SO4
K2Cr2O7+4H2SO4= K2SO4+Cr2(SO4)3+4H2O+3[O] As you can see during this reaction you obtain the O that you need for the oxidation of alcohol.
6 FeSO4 + K2Cr2O7 + 7 H2SO4 = 3 Fe2(SO4)3 + K2SO4 + Cr2(SO4)3 + 7 H2O
orange
K2Cr2O7 + 6 KI + 7 H2So4 = Cr2(So4)3 + 4 K2So4 + 3 I2 + 7 H2O
C2H2 or (HCtriplebond CH) --20%H2SO4,HGSO4,60 to 80 dgree--> CH3CHO --k2Cr2O7/conc. H2SO4 [O]--> CH3COOH --Ca(OH)2--> (CH3COO)2Ca --Dry distillation-->CH3COCH3
2K2Cr2O7+ 8H2SO4+ 3C2H5OH --> 2Cr2(SO4)3+ 2K2SO4 + 3CH3COOH + 11H2O
FeCl2 + 2KMnO4 --> Fe(MnO4)2 + 2KCl
k2cr2o7+FeSO4+H2SO4 --> Cr2(SO4)3+Fe2(SO4)3+K2SO4+H2O
K2Cr2O7(aq) + 3SO2(g) + H2SO4(aq) Cr2(SO4)3(aq) + K2SO4(aq) + H2O(l)
2K2Cr2O7 + 2H2SO4 + 3C2H5OH ---> 2Cr2(SO4)3 + 2K2SO4 + 3CH3COOH + 11H2O.