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Because the drag coefficient increases when the chute opens.
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Force down (newtons) = mass (m) * acceleration due to gravity (g)
Force up (newtons) = velocity2 * drag coefficient
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Terminal velocity is where up and down forces balance.
Say mass (m) = 100 kg, g = 9.82, then force down = m * g = 982 newtons, say terminal velocity (v) prior to chute opening = 70 m / s, then force down = force up so 982 = v2 * drag coefficient, so drag coefficient = 982 / 4900 = 0.2
without chute.
Terminal velocity with chute open, say 8 metres / sec, so drag coefficient
= 982 / 64 = 15.34 with chute open.
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∙ 12y ago
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