Because the potential difference V would be the same
I = V/R
As V remains the same, then as R is the same then I too would be the same
In a parallel circuit, the same (supply) voltage will appear across each branch. So, in your example, 12 V will appear across each of the 24-ohm resistors. To find the current through each resistor, then, you simply divide the supply voltage by the value of that resistor. Since the supply current is the sum of the two branch currents, to find the supply current, you simply add together the currents passing through each resistor.
in a parallel circuit resistance decreases increasing the current.
-- The current in each individual resistor is (voltage across the whole circuit) divided by (the resistance of the individual resistor). -- The current in any individual resistor is less than the total current in the circuit. -- The total current in the circuit is the sum of the currents through each individual resistor.
When resistors are connected in series in a circuit . the voltage drop across each resistor will be equal to its resistance, as V=IR, V is direct proportional to R. An A: The relationship is that the current will divide for each paths in a parallel circuit and the voltage drop across each will be the source voltage. In a series circuit the current will remain the same for each component but the voltage will divide to reflect each different component value. And the sum of all of the voltage drops will add to the voltage source
A circuit can be arranged in either a series or parallel configuration. In a series circuit, the components are connected in a single path, so the same current flows through each component. In a parallel circuit, the components are connected in multiple paths, allowing different currents to flow through each component.
In a parallel circuit, the same (supply) voltage will appear across each branch. So, in your example, 12 V will appear across each of the 24-ohm resistors. To find the current through each resistor, then, you simply divide the supply voltage by the value of that resistor. Since the supply current is the sum of the two branch currents, to find the supply current, you simply add together the currents passing through each resistor.
The total resistance of a set of resistors in parallel is found by adding up the reciprocals of the resistance values, and then taking the reciprocal of the total. By removing a resistor the total current will lower. If you short out the parallel circuit as suggested it will take out the fuse that should be protecting the circuit.AnswerShorting-out a resistor in a parallel circuit, will act to short out the entire circuit, therefore, significantly increasing, not lowering, the current! And, as the previous answer indicates, this short-circuit current will operate any protective devices, such as a fuse.In a parallel circuit current does not lower but it will be increase if shorting-out one resistor in the two resistor parallel circuit, the circuit will become very low resistive and the larger current will flow through the short path.
I don't know what the parallel circuit has to do with it. You've onlygiven me a resistor and the current through it.When 0.03A of current passes through a 1,000Ω resistor, the resistordissipates energy at the rate of 0.9 watt.
in a parallel circuit resistance decreases increasing the current.
In parallel circuit the current through the resistors are different in values depending upon the values of resistors. But the sum of the currents across all the resistors will be equal to the current through the sourcgsvg bdjasuhafyuhda
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-- The current in each individual resistor is (voltage across the whole circuit) divided by (the resistance of the individual resistor). -- The current in any individual resistor is less than the total current in the circuit. -- The total current in the circuit is the sum of the currents through each individual resistor.
When resistors are connected in series in a circuit . the voltage drop across each resistor will be equal to its resistance, as V=IR, V is direct proportional to R. An A: The relationship is that the current will divide for each paths in a parallel circuit and the voltage drop across each will be the source voltage. In a series circuit the current will remain the same for each component but the voltage will divide to reflect each different component value. And the sum of all of the voltage drops will add to the voltage source
The current through each resistor is equal to the voltage across it divided by its resistance for series and parallel circuits.
It depends on the purpose for installing the resistor. If the intent is to decrease current flow, the resistor must be connected in series with the load. If the purpose is to increase current flow, the resistor must be connected in parallel with the load. To connect a resistor in series, connect the resistor to one side of the power source, in line with the load. This will decrease circuit current flow. To connect a resistor in parallel, connect the resistor between the positive and negative sides of the power source, which will effectively connect the resistor across the load . This will increase current flow through the circuit. However, before connecting a component in parallel, make sure the increase in current flow will not exceed the current rating of the circuit or fuses/breakers will blow.
The potential difference remains the same over the components in parallel and the current splits up proportianally to the components conductances. The components conductances add up to give the combined conductance of the parallel circuit. Conductance is 1 / resistance
True...!