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the flammability of alkanes decreases as the hydrocarbon chains increase in length their evapouration rates decrease as longer chained molecules have higher boling points so temperatures must be high for them to evaporate therefore there is no fumes or vapours for longer chained alkanes at room temp like nonane and so on these hydrocarbons need higher temp to produce vapours n therefore will not burn with just a match
Petrol has a higher value of the heat of combustion.
Oxygen is neither combustible nor explosive, it is merely the chemical needed for combustion to take place. As such, the higher the concentration of oxygen, the higher the rate of combustion, provided that combustible material is present.
Melting points are determined by the strength of interaction between molecules in a solid. The greater the force of interaction, the higher the melting point. Molecular interactions are the result of the attraction between partially charged molecules or ions in a solid. Alkenes have little or no charge; they are nonpolar. In order for alkenes to stick to each other in a solid, they need to have partial charge induced randomly. This is known as London Dispersion Force. The probability of a partial charge occurring is increased when the size of a molecule's electron cloud increases. Bigger alkenes have bigger electron clouds, and thus have more powerful London dispersion force. More intermolecular force means higher melting points.
The Saw-Tooth pattern represents the crystal lattice of straight chain alkanes with terminal ends lying in the same side while the alternation effect shows how the melting point from odd to even positions of carbon atoms is higher than from even to odd Carbon atoms.
the flammability of alkanes decreases as the hydrocarbon chains increase in length their evapouration rates decrease as longer chained molecules have higher boling points so temperatures must be high for them to evaporate therefore there is no fumes or vapours for longer chained alkanes at room temp like nonane and so on these hydrocarbons need higher temp to produce vapours n therefore will not burn with just a match
Complete oxidation of alkanes by oxygen yeilds carbon dioxide and water. Alkanes oxidation by O2, (CxH2x+2) + O2 = x CO2 + x+1 H2O. With Halogens it would be CyH2y+2 + X2 = CyX2y+2 + (y+2) HX. Carbon Carbon bonds often do not break in halogen oxidation. "often"
Alkanes have single bonds while Alkenes have double bonds.CnH2n+2 is the general formula for alkanes.CnH2n is the general formula for alkenes.
the alkanes are saturated and contains more atoms so therefore contain more electrons this results in stronger dispersion forces the alkenes and unsaturated contain less atoms less electrons weaker dispersion force compared to the alkane
The combustion of heptane and pentene will differ in that because pentene is an alkene, it is more likely to experience incomplete combustion because of the higher ratio of carbon to hydrogen than in alkanes. Some carbon will not be oxidized fully and will make soot. Heptane will have a higher heat of combustion than pentene because it has more bonds to be broken.
The higher the air density, the more oxygen available for combustion.
Petrol has a higher value of the heat of combustion.
in complete combustion the amount of oxygen is higher/more than the amount of oxygen in incomplete combustion. Heat needs oxygen.
Oxygen is neither combustible nor explosive, it is merely the chemical needed for combustion to take place. As such, the higher the concentration of oxygen, the higher the rate of combustion, provided that combustible material is present.
this is because of the presence of intermolecular hydrogen bonding in the polar molecules. energy is needed to over come the attractive forces resulting in higher boiling point values.
oxygen
Melting points are determined by the strength of interaction between molecules in a solid. The greater the force of interaction, the higher the melting point. Molecular interactions are the result of the attraction between partially charged molecules or ions in a solid. Alkenes have little or no charge; they are nonpolar. In order for alkenes to stick to each other in a solid, they need to have partial charge induced randomly. This is known as London Dispersion Force. The probability of a partial charge occurring is increased when the size of a molecule's electron cloud increases. Bigger alkenes have bigger electron clouds, and thus have more powerful London dispersion force. More intermolecular force means higher melting points.