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Why is it if MARIE has 4k words of main memory and addresses must have 12 bits?
Wiki User
∙ 12y ago
4K (4096) of addressable space is defined by 12 bits of address space, because 212 = 4096.
Wiki User
∙ 12y ago
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What is the bit capacity of a memory that has 1024 addresses and can store 8 bits at each address?
1024 bytes is 8192 bits.
If a memory has 512 words how many bits should the address registry have?
9
How many address bits would be required for a memory that stores 64 4-bit words?
It requires 6 bits to address 64 words. It does not matter what the word size is.
How many words are there in an address space specified by 24 bits and the corresponding memory space by 16 bits?
address space=24bits => (2 Power 24)=16M words
How many bits of mask are required to provide 30 host addresses?
5 bits
How many bits of address bus are required to address 1mb memory?
You need 20 bits of address bus to address 1 Mb of memory.
What does the number of bits used to represent a memory address determine?
The number of bits used to represent a memory address determines the number of different addresses that can be formed. If the number of bits is N, then 2N addresses can be formed.If N is 16, as it is in the 8085, then 216 = 65,536.If N is 20, as it is in the 8086/8088, then 220 = 1,048,576.If N is 24, as it is in the IBM 360/44, then 224 = 16,777,216.If N is 32, as it is in most 32 bit modern processors, then 232 = 4,294,967,296.If N is 64, as it is in most 64 bit modern processors, then 264 = 18,446,744,073,709,551,616.Note that the amount of addressable memory is not the same as the amount of physical memory. As addressability goes up, often physical memory does not match it, which means that effective addressability is limited.
How long are Ethernet Mac addresses?
Ethernet addresses are 48 bits long - not 32 bits long like IP addresses. Different single network standards have different address lengths. Ethernet addresses are called MAC addresses for other reasons, Media Access Control.
Consider a logical address space of eight pages of 1024words each mapped onto a physical memory of 32 frames how many bits are there in the logical address?
As was given for a 4 Page, 1024 words & 64 frames (shown below) 4 pages -> 2^2 bits 1024 bytes -> 2^10 bits 64 frames -> 2^6 bits Therefore: Logical memory = 2+10=12 bits Physical memory = 10 +6 =16 bits The answer for this problem is 13. 8 pages -> 2^3 bits 1024 bytes -> 2^10 bits 32 frames -> 2^5 bits Therefore: Logical memory = 3+10=13 bits (Page + Word) Physical memory = 10 + 5 =15 bits (Word + Frame)
What is byte addressable memory?
a byte is abasic storage unit in memory. when application program instructions and data are transferd to memory from storage devices. byte addressable memory refers to memory address that is accessed one byte (8 bits) at a time as opposed to 2 byte(16 bits), 4 byte(32 bits) or 8 byte(64 bits) addressable memory.
What is memory measurement?
The memory in the computer is stored in the form of bits and bytes
How many bits are necessary to assign addresses to 62 hosts?
6
