The question is not clear; the concentration of salt in water can be very variable.
At the saturation concentration a true dissolution is not possible and the concentration remain constant.
The electrical conductivity of the solution will be higher if the concentration of NaCl increase.
The freezing point of the solution depends on the NaCl concentration.
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If you think to an isotonic solution the concentration is 0,9 g NaCl/100 g solution.
A solution with a concentration of NaCl higher than 9 g/L is hypertonic.
The concentration of NaCl is 263 g/L
This is equivalent to a concentration of 6,73 g/L NaCl.
The concentration of NaCl is 15,73 mg/100 mL.
Get moles NaCl and change 245 ml to 0.245 Liters. 3.8 grams NaCl (1 mole NaCl/58.54 grams) = 0.0650 moles NaCl Molarity = moles of solute/Liters of solution Molarity = 0.0650 moles NaCl/0.245 Liters = 0.27 M NaCl ----------------------
This concentration of NaCl is 2,6 g NaCl/100 mL solution.
The concentration is the same !
4.09 m