different microprocessors take different number of states. without knowing processor its not possible to comment.
The STA 4200H instruction in the 8085 requires 4 machine cycles and 13 T states to complete its fetch, processing, and execution. Cycle One: Opcode fetch, 3 T states plus one opcode process state. Cycle Two: Opcode address byte 00H fetch, 3 T states Cycle Three: Opcode address byte 42H fetch, 3 T states Cycle Four: Accumulator store, 3 T states. Each cycle will have additional T-Ready states as needed by the READY pin. 13 T states is the minimum. The LDA instruction will also require 13 T states, with the last cycle being a read cycle instead of a write cycle.
there are 4 phases in instruction cyclefetchdecodeexecutestore
There are many different advantages of a microprocessor based system. Some of these include that it only uses 3 components so it is simple to use and install and it will increase your memory.
1)Fetch 2)Decode 3)Execute 4)Store
disadvantages:1.It has limitations on the size of data. 2.Most Microprocessor does not support floating-point operations. 3.over heating physically, 4. not bit addressable,
The STA 4200H instruction in the 8085 requires 4 machine cycles and 13 T states to complete its fetch, processing, and execution. Cycle One: Opcode fetch, 3 T states plus one opcode process state. Cycle Two: Opcode address byte 00H fetch, 3 T states Cycle Three: Opcode address byte 42H fetch, 3 T states Cycle Four: Accumulator store, 3 T states. Each cycle will have additional T-Ready states as needed by the READY pin. 13 T states is the minimum. The LDA instruction will also require 13 T states, with the last cycle being a read cycle instead of a write cycle.
The STA instruction in the 8085 has 13 T states, 4 for opcode fetch, 3 for low half immediate address fetch, 3 for high half immediate address fetch, and 3 for data write.
4 states for opcode fetch and decode 3 states for each byte to retrieve the target (call) address 3 states for each byte of PC to push on the stack 1 state for each decrement of the stack pointer
Each instruction requires specific time for the execution of instruction and this time is called instruction cycle. Each instruction cycle consists 1 to 5 machine cycle -- opcode fetch, memory read, memory write, IO read, IO write and each machine cycle consist 3 to 6 T - states. Time required to execute 1 T-state = 1/ operating frequency of 8085 Microprocessor for example operating frequency = 2MHz then time required to execute 1 T-state = 0.5 uSec example: Calculate time required to execute instruction MOV C, A sol: This instruction has one machine cycle i.e. opcode fetch (In any instruction 1st cycle is always opcode fetch and opcode fetch consists 4 to 6 T state depend on the operation of particular instruction) so to execute MOV C, A required 4T states so time required to execute this instruction is 4*0.5usec = 2usec any other queries pls contect: nileshbahadure2000@yahoo.co.in example:Calculate the time required to execute LXI H,2000H sol:Here we have to draw opcode fetch and two memory reads as two bytes 00H and 20H have to be read from memory. i.e, opcode fetch+Memory reads *2(bytes address) =4+3+3 so to execute LXI H,2000H,the required T-states is 10T and time is 10*0.5usec=5usec
The MOV A,B instruction requires 1 machine cycle and 4 T-states, 3 to fetch the opcode, and 1 to decode/execute it.
Summary − So this instruction XCHG requires 1-Byte, 4-Machine Cycles (Opcode Fetch) and 4 T-States for execution as shown in the timing diagram.
It will require 4 machine cycles, 1.opcode fetch 2.memory read 3. memory read 4. memory write
The question is unclear, but it looks like it meant to ask when the first microprocessor was invented. That was the Intel 4004, invented in 1971. It was the first single chip microprocessor, and the first microprocessor available commercially. The 4004 was a 4 bit processor, with a 12 bit address bus and an 8 bit opcode. Everything was multiplexed, 4 bits at a time, in 8 clock cycles per instruction.
Hi, The equation to find the number of instructions with n-bit opcode is 2^n. If your opcode is n=4, the it's 2^4 which is 16. So with a four bit opcode you can have 16 different instructions. ---- 11 levels
RET instruction needs 3 machine cycles. One to fetch and decode the instruction(4 T states), and two more machine cycles(i.e. 2*3=6 T states) to read two bytes from the stack(stack is exterior to microprocessor, stack is in R/W memory, so to exchange data with stack needs machine cycles). Thus, RET instruction needs total 3 machine cycles and 10 T-states.
Fetch is having a season 4! it premieres in the summer or fall! Fetch is having a season 4! it premieres in the summer or fall! Fetch is having a season 4! it premieres in the summer or fall!
The winner of Fetch! with Ruff Ruffman season 4 is Liza.