because it has many number of shells.
Ionisation energy is defined as the amount of energy required to remove the most loosley bound or valence electron from an atom. The lower the ionisation energy, the easier it is to remove the electron. Once the electron has been removed, electroneutrality is lost and the atom develops a positive charge and is known as a positively charged ion. Now, an ionic bond is the bond formed between two oppositely charged species. For example, a bond between a positively charges sodium ion and a negatively charged chloride ion. The lower the ionisation energy, the easier it will be for the atom to lose an electron, thereby forming a positively charged species which will be capable of forming an ionic bond with a negatively charged species. Or lower the ionisation energy, the greater is the tendency to form an ionic bond.
Well between Magnesium and Aluminium there is a change in sub-shells as the outer most electron in Aluminium is within the p-shell, where as the Magnesium is within the s-shell . This means the electron within Aluminium is further away from the nucleus, in addition there is more shielding involved. Consequently the electron needs less energy to force it away phosphorus and sulphur and are in the same shell , however sulphur contains a extra electron to phosphorus. This extra electron is paired with another electron which in turn as the both are negatively charge repel each other , making it easier to force the electron out :)
The further you are down the halogen group (group 7) the lower the 1st ionisation energy (amount of energy required to remove 1 electron from the atom) is. This is because the electron in question becomes further from the positive charge of the nucleus the more electron shells there are, and electron shielding (the blocking of the effect of the positive charge's attraction) is increased.
Ar P Al Na K In general the ionisation energy (this answer refers to first ionisation energy, although most of the principles mentioned here apply to all ionisation energies) increases as one moves across the period, this is due to an increasing nuclear charge and decreasing atomic radius (recall that F=(kq1q2)/r2 ). However there are exceptions to this, notably, on moving from group II to group III we see that ionisation energy decreases, like wise on moving from group V to group VI. The first of these decreases is a result of the additional electron occupying the p orbital (and therefore experiencing a lesser effective nuclear charge). The second decrease (which is less marked) is due to the additional electron being "placed" into an orbital already occupied by another electron (an electron pair is formed), these electrons have the same charge and therefore repel each other, as they are in the same orbital the repulsion is particularly strong, therefore the effective nuclear charge is less and first ionisation energy is lower. I hope this answer is acceptable, for more information see the Wikipedia article on electronic configuration.
On progression from magnesium oxide to barium oxide, the metal ion has an increasing atom size, with a decreasing ionisation energy and can easily lose one electron to form more the hydroxide ions (or in another point of view leads to lower activation energy and hence faster reaction) this is why there is an increase in pH.
no sulfur is practically a gas
Ionisation energy is defined as the amount of energy required to remove the most loosley bound or valence electron from an atom. The lower the ionisation energy, the easier it is to remove the electron. Once the electron has been removed, electroneutrality is lost and the atom develops a positive charge and is known as a positively charged ion. Now, an ionic bond is the bond formed between two oppositely charged species. For example, a bond between a positively charges sodium ion and a negatively charged chloride ion. The lower the ionisation energy, the easier it will be for the atom to lose an electron, thereby forming a positively charged species which will be capable of forming an ionic bond with a negatively charged species. Or lower the ionisation energy, the greater is the tendency to form an ionic bond.
The ionisation enthalpy of potassium is lower than that of sodium.
Well between Magnesium and Aluminium there is a change in sub-shells as the outer most electron in Aluminium is within the p-shell, where as the Magnesium is within the s-shell . This means the electron within Aluminium is further away from the nucleus, in addition there is more shielding involved. Consequently the electron needs less energy to force it away phosphorus and sulphur and are in the same shell , however sulphur contains a extra electron to phosphorus. This extra electron is paired with another electron which in turn as the both are negatively charge repel each other , making it easier to force the electron out :)
Because in Boron there is a complete 2s orbital and the increased shielding of the 2s orbital reduces the ionisation energy compared to that seen in Beryllium.
It is about first ionization energy. It is less than alkaline earth metals.
Because with the 2nd ionisation of K, you are trying to take an electron from a fully filled orbital (octet rule) whereas with calcium it is getting down to a fully filled orbital
because it lower than Ba as you go down ionization energy increases
Because the force of attraction between the nucleus and the outer most electron is less. In addition, most metals (but not all) will gain the stable electronic configuration of the nearest noble gas if they lose electron.
Oxygen has a lower electronegativity than fluorine (3.5 as compared to 4).
The further you are down the halogen group (group 7) the lower the 1st ionisation energy (amount of energy required to remove 1 electron from the atom) is. This is because the electron in question becomes further from the positive charge of the nucleus the more electron shells there are, and electron shielding (the blocking of the effect of the positive charge's attraction) is increased.
The production per hectare is lower.