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A: THE EMITTER resistor sole function is to provide stability if it is by passed by a capacitor then this resistance will change due to frequency since as frequency increases the impedance decreases. The total gain will change accordingly
A photo resistor decreases in resistance as illumination increases. I don't believe there are any discrete components that accomplish what you are asking. You may need to use a photo resistor, combined with a transistor to invert this operation.
If the voltage applied across the resistor remains constant, then as the resistance of the resistor decreases, the current through it will increase. Consider Ohm's Law: E = IR In this formula, in order for 'E' to remain constant as 'R' decreases, 'I' must increase. Another form of Ohm's Law: I = E/R If 'E' remains constant, then the value of the fraction increases as its denominator 'R' decreases.
if we remove a resistor from the parallel connection the effective resistance value will be increased.
This depends on the type of conductor. If the conductor has a positive coefficient the resistance will increase. If the conductor has a negative temperature coefficient the resistance will decrease.
The impedance of a component (inductor or capacitor) will change with frequency - resistor impedances will not. Inductor impedance - j*w*L Capacitor impedance - 1/(j*w*C) L = inductance, C = capacitance, j = i = imaginary number, w = frequency in radians The actual inductance and capacitance does not change with frequency, only the impedance.
at low frequency less than 50hz the voltage gain decreases with decreasing frequency and at mid frequency{50hz to 20khz} the voltage gain is uniform because resistor value are independent of frequency change and at the high frequency votage gain falls.
A: THE EMITTER resistor sole function is to provide stability if it is by passed by a capacitor then this resistance will change due to frequency since as frequency increases the impedance decreases. The total gain will change accordingly
A photo resistor decreases in resistance as illumination increases. I don't believe there are any discrete components that accomplish what you are asking. You may need to use a photo resistor, combined with a transistor to invert this operation.
Resonant frequency is the frequency where the voltage across the tuned filter is maximized. Inject a sine wave through a resistor into the filter, and adjust frequency for peak amplitude.At higher frequencies, such as RF, this becomes interesting because everything disturbs the circuit, including the resistor, because it is no longer a pure resistor. Measurment of resonant frequency in RF circuits is best done in situ.Resonant frequency is measured like all frequencies in Hertz or cycles per second.
If the voltage applied across the resistor remains constant, then as the resistance of the resistor decreases, the current through it will increase. Consider Ohm's Law: E = IR In this formula, in order for 'E' to remain constant as 'R' decreases, 'I' must increase. Another form of Ohm's Law: I = E/R If 'E' remains constant, then the value of the fraction increases as its denominator 'R' decreases.
For a low frequency source, the voltage across the inductor tends to zero because its impedance is proportionnal to source frequency, whereas the voltage across the resistor tends to the voltage source value.
The reason why resistor voltage decreases while a capacitor discharges is because the resistor acts like a source of electrical energy. As the capacitor discharges, it draws energy from the resistor, which causes the voltage across the resistor to decrease. This is because the capacitor is acting like a drain, and is taking energy out of the resistor, thus causing the voltage across the resistor to decrease. The resistor and capacitor work together in order to create a discharge circuit. This is done by connecting the capacitor to the resistor, and then to a voltage source. The voltage source supplies the energy to the resistor, and then the resistor transfers this energy to the capacitor. As the capacitor discharges, it takes energy from the resistor, which causes the voltage across the resistor to decrease. In order to understand this process better, it is important to understand the basics of Ohm's Law. Ohm's Law states that the voltage across a resistor is equal to the current through the resistor multiplied by the resistance. As the capacitor discharges, it takes energy from the resistor, which means that the current through the resistor decreases, and therefore the voltage across the resistor will also decrease.
You change a variable resistor in the the tuning circuit. The value of the resistor dictates the frequency that the radio is receiving.
the voltage across that resistor will increase if it is in series with the other resistors. the current through that resistor will increase if it is in parallel with the other resistors.
A: That resistor is there to limit the current to the LED it can be any value if the voltage is decreased or increased or no resistor if the voltage across the led is equal to the forward voltage drop.
if we remove a resistor from the parallel connection the effective resistance value will be increased.