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Why the power drawn across 40 watt bulb more than 60 watt bulb?
Wiki User
∙ 12y ago
It isn't more, it is less if bulbs are of the same type.
Wiki User
∙ 12y ago
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Why terminal potential difference is decrease when current in the circuit is increased?
If the terminal voltage decreases when more current is drawn, that is due to the internal resistance of the power supply. Every power supply has a limit to how much current can be drawn. It is limited by the internal resistance and due to ohms law the more current drawn through a resistor, then the more voltage is produced across it. This is in opposition to the terminal voltage and is subtracted from it.
What consumes more power a light bulb or a refrigerator when they are on?
Refrigerator- it takes more power to kick on and it pulls more electricity than a light bulb
How are light bulbs efficiency increased?
The brightness of a standard bulb is directly proportional to the amount of voltage drop across the bulb itself. Thus, to increase the brightness :-Pass more current across the bulb by reducing the resistance of the circuitIncrease the voltage across the bulb, or the circuit. Change the supply.
What would be the voltmeter reading if the lamp across which it is placed has a broken filament?
A voltmeter connected across the broken (open) filament of a light bulb reads the full voltage of the power supply whether the bulb is in a series or parallel circuit. -- In a series circuit with other components in series with the bulb, this reading tells you that at least one of the components is open, possibly the filament. -- In a parallel circuit with other components in parallel with the bulb, or with the bulb connected directly to the power supply, this reading tells you nothing ... the voltmeter reads the full power supply voltage whether the bulb is open or good. The voltmeter isn't a very helpful measurement to identify an open filament. An ohmmeter, with the power to the circuit turned off, is much more helpful.
What consumes more power a light bulb or toaster?
By far a toaster draws more current than a light bulb.
What is the Electrical power for a lightbulb?
The power rating for a light bulb (like "40 W") tells how much electrical power the light bulb uses. All of the power used by the bulb is either converted into light or heat. In an incandescent bulb, most of the energy becomes heat. In a fluorescent bulb, more of it becomes light.
Which bulb uses more electricity40 watts100 watts or 120 watt?
The higher the wattage the more you pay for power. So it costs more to operate a 120 watt bulb than it does a 100 or 40 watt bulb.
Does a long bulb have more potential difference than a round bulb?
The long and swirly one is a power saving one.
Why a rotor of an alternator at rated power dissipates more heat at a low power factor load than at a high power factor load?
at lower power factor current drawn by load is high and at higher pf the current drawn is less...
How can you connect bulbs in series?
A Bulb can be connected in a series in such a way that the energy source which is applied want to flow equally across the bulbs connected in series. A Bulb has to knobes or holds in which we supply the power. Assume one knob as a positive voltage absorbing source and other has a negative voltage absorbing source. When we connected in such a way that we can apply the voltage continuously in which the bulb will blow easily. When two or more bulbs are connected in series like end of the knob of one bulb i.e., negative to the next positive of the next bulb in series and negative of second bulb to the positive of the third bulb. Then the voltage splits equally across the bulbs connected.
100w bulb and 60w bulb connected in parallel to 220v which will glow brightly?
Total supply voltage = 220vrated power of first lamp= 100 wattso current though it, I=p/vI=100/220=.45 ampsResistance offered by first lamp=220/.45= 488 ohms( i avoid fractions)..............................................................rated power of second lamp=60 wattsvoltage is same, so current through it = 60/220=.27 ampsresistance of second lamp = 220/.27=814 ohms( i avoid fractions).........................................................................power drawn by first lamp =I12 R=(.45)2 * 488 =98.82(=100)power drawn by second lamp =I22 R=(.27)2 * 814 =59(=60)...................................................................................SO 100 WATT BULB WILL GROW BRIGHTER AS IT HAS MORE POWER
How do you think energy transfers would be different in a lamp using a more efficient light bulb?
It would be more different since it will take up more power than the less efficient light bulb. Instead of using all the solar power it will probably need the forces of 2 energies to light the bulb.
