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Why is the value of acceleration due to gravity at the poles is greater than at the equator?
Wiki User
∙ 13y ago
I think there are two reasons:
- Gravitational attraction between two masses is inversely proportional to the square of the distance between their centers of mass, and since the earth is not quite a sphere, you're closer to the center of the earth when you're at one of the poles than you are at the equator.
- The earth is rotating at one degree every four minutes, which means that everything on the equator is circling the earth at a linear speed of about 1040 miles per hour. The resulting inertia, which would fling everything into space like an object on a spinning turntable if not for gravity, gets subtracted from gravity.
Wiki User
∙ 11y ago
Wiki User
∙ 10y agoBecause 'g' is inversely proportional to the square of the distance from
the Earth's center, and the surface is slightly closer to the Earth's center
at the poles than it is at the equator.
Wiki User
∙ 13y agoThe pole are slightly closer to the Earth's center. Also, at the equator there is some effect due to the rotation of Earth (centrifugal force), that partially offsets the gravity.
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Where is acceleration due to gravity greater?
It is greater at poles than at equator.
Is there any difference between the value of g at the equator and the poles?
it is greater at poles than equator
Why does the weight of an object change when it is moved from the equator to the poles?
Because of centripetal acceleration you will weigh a tiny amount less at the equator than at the poles.
Gravity is greater than what?
poles
What is the acceleration due to gravity at 49 degrees north latitude?
The acceleration due to gravity is not a constant across the face of the earth, as is astutely suggested from the nature of the question. The acceleration due to gravity on earth is given by g , and it is about 9.789 m/sec2 at the equator and about 9.823 m/sec2 at the poles. The observer might conclude with a bit of thought that the effect of gravity at the poles is a bit higher because of the shape of the earth, which is sometimes termed an oblate spheroid by astrophysicists. The earth is flattened up top and down bottom, and is a bit "fatter" in the middle. That means that a body on the equator is farther from the effective center of pull of gravity of earth. It will weigh less on the equator. And more on the poles where gravity is higher. At 49 degrees north latitude, the value of g is some 9.8707 m/sec2 there. Note that the general value often given for g is some 9.8 m/sec2, and it is applied for much work in "regular" mechanics.
Where is acceleration due to gravity greater?
It is greater at poles than at equator.
Does gravity have a stronger pull at the eatrh poles then it does on the equator?
no, but the electromagnetic field of the earth does.
Why is gravity stronger at the poles than the equator?
The closer an object gets to the center of the earth, the greater the pull of gravity on that object.
Why would an object way less at the equator than at the poles?
Not for sure but it seems like there would be more gravity at the equator than at the poles. The earth rotates and creates a centrifugal acceleration at the equator the counters the force of gravity. acceleration due to gravity =GM/R2 acceleration due to rotation =V2/R So gravity at the equator is GM/R2 - V2/R
Gravity is greater at the what?
Gravity increases from about 9.780 m/s2 at the Equator to about 9.832 m/s2 at the poles. This means an object will weigh about 0.5% more at the poles than at the Equator.
How does the acceleration of gravity depend on it's distance from the center of the Earth?
acceleration due to gravity is given by, g=GM/R2 Hence distance from the earth increases g decreases and viceversa. So g at poles is greater than g at equator.
Is value of g is greater at the poles or at equator?
The expression for acceleration due to gravity isge=GMe/r2Acceleration due to gravity is inversely proportional to the square of the distance between the center of the Earth and the object. The acceleration due to gravity produced in an object on the surface of the Earth is dependent on the radius of the Earth. Earth is not a perfect sphere (slightly bulging out at the equator) its radius decreases as we move from the equator to the poles. At the equator and at sea level its value is about 9.78 m/s2 and at the poles it is 9.83 m/s2. Its mean value is taken as 9.8 m/s2 for all calculations.
Which best explains why the weight of an object is less at the equator than at the poles?
The earth is not a perfect sphere. The spin of the earth causes it to buldge out at the equator, which means the equator is further from the center of the earth then the poles are. The further an object is from the center of mass of another object, the less effect the gravity of those objects will have on each other. So at the equator, an object is being effected less by the gravity of the earth then it is at the poles.
Is there any difference between the value of g at the equator and the poles?
it is greater at poles than equator
Gravity is greater at the?
poles
Where the gravitational force is greater in equator poles or Mt. Everest?
poles
Why does the weight of an object change when it is moved from the equator to the poles?
Because of centripetal acceleration you will weigh a tiny amount less at the equator than at the poles.
