The Battle of Long Tần is arguably the most famous battle fought by the Australian Army during the Vietnam War. It was fought in a rubber plantation near the village of Long Tần, about 4 km north-east of Vung Tau, South Vietnam on August 18
The Australians lost many of their men in the seige of Tobruk. The story is complicated. See the link below to read the entire story.
Lions are a tan color so they blend in with the environment . The long grasses they live in are tan.
Australians are so cool because we are Australians.
Yes, unless you tan every day. Your tan will only last so long. Otherwise, we wouldn't need to tan every summer.
I am Mexican , but I am much whiter toned then others, I get tan, but if I'm out in the sun to long I get a gross dark coulour
Translation: Kelie me dijo que trabajas mucho/*tan.... *tan....= 'so (hard/long, etc.)' (or you could use 'mucho' by itself)
Australians speak English so we just say.... street
i presume you mean do Australians call us poms? if so yes
Tan rica is: So delicious or So rich.
tan (A-B) + tan (B-C) + tan (C-A)=0 tan (A-B) + tan (B-C) - tan (A-C)=0 tan (A-B) + tan (B-C) = tan (A-C) (A-B) + (B-C) = A-C So we can solve tan (A-B) + tan (B-C) = tan (A-C) by first solving tan x + tan y = tan (x+y) and then substituting x = A-B and y = B-C. tan (x+y) = (tan x + tan y)/(1 - tan x tan y) So tan x + tan y = (tan x + tan y)/(1 - tan x tan y) (tan x + tan y)tan x tan y = 0 So, tan x = 0 or tan y = 0 or tan x = - tan y tan(A-B) = 0 or tan(B-C) = 0 or tan(A-B) = - tan(B-C) tan(A-B) = 0 or tan(B-C) = 0 or tan(A-B) = tan(C-B) A, B and C are all angles of a triangle, so are all in the range (0, pi). So A-B and B-C are in the range (- pi, pi). At this point I sketched a graph of y = tan x (- pi < x < pi) By inspection I can see that: A-B = 0 or B-C = 0 or A-B = C-B or A-B = C-B +/- pi A = B or B = C or A = C or A = C +/- pi But A and C are both in the range (0, pi) so A = C +/- pi has no solution So A = B or B = C or A = C A triangle ABC has the property that tan (A-B) + tan (B-C) + tan (C-A)=0 if and only if it is isosceles (or equilateral).
so they say.
What took you so long: ¿Por qué tardaste tanto tiempo