NaCl is not soluble in acetone.
Nothing happens. NaCl is virtually insoluble in acetone. Only 0.042 mg of NaCl will dissolve in 100 g of acetone at 25°C.
Any interaction occur.
according to the theory 'like dissolve like',polar solute will dissolve in polar solvent because these solute will ionise and get dissolved in ionised solvent. NaCl---Na+ + Cl- H2O---H+ + OH- thir is not so with acetone which is non-polar in nature.
Finger nail polish remover. must get kind with active ingrediant "Acetone".
NaI is solubale in acetone while NaCl is not soluable
Yes. Wet acetone will disolve sugar because of it's high water content, and although dry acetone will dissolve sugar, it will not do so in the way that wet acetone will.
No. Nail polish remover (usually acetone or a similar solvent) will not disolve cyanoacrylics (super glue) once the super glue has hardened.
Kitchen salt (NaCl) and other salts that are divided into charged ions are generally easily dissolved in water because of water's diaeletric properties. What can happen is water molecules encapsulate the ions, which they can have a natural affinity for.
No, because when you add acetone to acetone, all you are doing is adding more of the volume of acetone to acetone. You are just changing the amount of acetone, not anything chemically happening.
Yes, mainly there are 3 types of acetone: regular acetone, acetone with enriched formula, maximum strength acetone.
Acetone is the organic compound with the formula OC(CH3)2. The molecular shape of acetone makes it able to disolve many materials including plastics. This colorless, mobile, flammable liquid is the simplest example of the ketones. It is typically the solvent of choice for cleaning purposes in the laboratory owing to the fact that acetone is miscible with water, it is the solvent of choice for cleaning purposes in the laboratory. It is a common solvent for rinsing laboratory glassware because of its low cost, volatility, and ability to dissolve water. For similar reasons, acetone is also used as a drying agent.
So the since its SN1 it would be a two step process:1st step is the dissociation of the Cl so you get your carbocation.The second steps involves the Cl attaching to the NA+ and the I attaches with the carbocation.The acetone is not soluble with the NaCl so at the end of the reaction you'll have some precipiate from it.