Yes and no. The globe, if it will fit the socket, will light, but it will be a dull red and useless.
Electrical fittings for 240 volts usually wont allow this as they are different fittings.
The later types called EF lights will probably not work.
No, it will be only half as bright as using the bulb on full voltage.
A light bulb connected between to wires, each having 300 volts to ground that are in phase, will not light, because there is no differential voltage available to do any work. If each wire has 300 volts to ground and are out of phase (600 volts between them) the light bulb will be lit, if it is rated at least for 600 volts, otherwise it will burn out.
Using the Electrical Power Law, which is:The current (measured in amps) equals the power (measured in watts) divided by the potential difference (measured in volts)So a light bulb designed to use 60 watts of power when supplied with 120 volts must draw 60 watts divided by 120 volts, which is a current of 0.5 amps.The same answer could be expressed in a few different ways:500 milliwatts500 mW"1/2 an amp" !
I = E/R = 120/25 = 4.8 amperes
The formula you are looking for is I = W/E. Amps = Watts/Volts.
Ohm's Law: Resistance is voltage divided by current Power Law: Power is current times voltage Combining them gives: Resistance is voltage squared divided by power 220 volts squared divided by 100 watts = 484 ohms. Note that this is hot resistance. If you measure the bulb in the cold state, you will get an entirely different, smaller, value, due to the extreme temperature coefficient of the filament. Independently of that, since you ask for peak voltage, that means you are talking about an AC voltage source. We have to assume a sinusoidal waveform, and that the 220 volts was the RMS value. In this case, the peak value is simply the RMS value multiplied by the square root of 2, i.e. 0.707..., making the peak value 311 volts.
A light bulb connected between to wires, each having 300 volts to ground that are in phase, will not light, because there is no differential voltage available to do any work. If each wire has 300 volts to ground and are out of phase (600 volts between them) the light bulb will be lit, if it is rated at least for 600 volts, otherwise it will burn out.
it all depends on what the bulb is rated for4 extra volts on a 120 volt bulb is negligable4 extra volts on a 1 volt bulb will definitely pop the element, but I don't think it would explodeAnswerDepends on the bulb voltage, but it shouldn't explode. If it's a 6volt bulb or lower, it would burn out quickly.If it's a 12volt bulb or higher, it may have a shorter life, but it would be brighter.
Electricity in your house or anywhere else comes in volts. When you screw in a light bulb, you screw it in to an electrical socket that has a certain number of volts. The socket can have 3 volts like a flash light, 12 volts like a car, 120 volts like American houses, or 240 volts like some Latin American houses. The light bulb is designed to work with one of those voltages. If you put a 240 volt bulb in a 120 volt socket, it will glow extremely dim. If you put a 120 volt light bulb in a 240 volt socket, it will glow extremely bright, but it will burn out in a short period of time. So you should put a 120 volt bulb in a 120 volt socket. In the United States, you will not have that trouble. However, if you take your yacht to a foreign country, you might put your light bulb in the wrong socket.Another AnswerA lamp will only operate at its rated power when subject to its rated voltage. So, if you want your lamp to operate at its rated power, you must connect it to a supply which provides its rated voltage
When the alternator on a vehicle is in the charging mode its output is close to 14.5 volts. If a bulb is rated at 12 volts, which is the voltage of a vehicle battery at rest, when the alternator comes on line at a higher voltage the life span of the bulb will be shortened.
Yes, in fact that is what a rough service bulb is rated at. The bulb used on a 120 volt system will have a reduced wattage output as to what it would be on 130 volts.
The current is half an amp because amps times volts equals watts.
Yes, a 103 volt source will light a 60 watt light bulb. The relationship of the bulb's wattage output at a lower voltage, as to the normal voltage that the bulb is rated to operate on, the light output will be lower.
Onions don't have volts.
it varys from light bulb to light bulb.
V on a light bulb means volts. W means watts.
120 volts.
110 volts is what comes out of an average wall socket in America. A 100-watt bulb would be powered by 110 volts. You need to be more specific in your question to get a good answer. Small can't be measured.