No. Copper will not replace hydrogen in sulfuric acid because it is less reactive than hydrogen.
Cu is oxidized. The oxidation number goes from 0 in Cu to +2 in CuSO4. S is reduced. The oxidation number goes from +6 in H2SO4 to +4 in SO2. The oxidizing agent is H2SO4 since it causes Cu to be oxidized. The reducing agent is Cu since it causes S in H2SO4 to be reduced.
In order for something to act as an oxidizing agent, it itself must be reduced, or put in other terms, it must be able to gain electrons. And for the record, the H2SO4 in order to react with Cu and to oxidize it, must be HOT and CONCENTRATED. Just putting Cu in some H2SO4 will not produce a reaction. The reaction of Cu + H2SO4 is as follows: Cu(s) + 2H2SO4(l) ---> Cu2SO4(s) + SO2(g) + 2H2O(g) ... note the states of each. In this reaction, the S of H2SO4 has gained electrons to form SO2, so it has been reduced and it has oxidized the Cu which went from Cu(s) to Cu^2+ in CuSO4. HCl is not capable of gaining electrons from Cu so it cannot oxidize the Cu.
Cu+H2SO4 Gives CU2(SO4)2+H2O+S2O2
H, Mg, Zn, Cu
It is exothermic. Take for example H2SO4 H2SO4 -> H+ + HSO4- This is very exothermic
CuSO4 Cu + 2H2SO4 -> CuSO4 + SO2 + 2H2O
Cu is oxidized. The oxidation number goes from 0 in Cu to +2 in CuSO4. S is reduced. The oxidation number goes from +6 in H2SO4 to +4 in SO2. The oxidizing agent is H2SO4 since it causes Cu to be oxidized. The reducing agent is Cu since it causes S in H2SO4 to be reduced.
H2so4 --> h+ + hso4- hso4- --> h+ + so42-
Cu + H2SO4 = CuSO4 + H2
In order for something to act as an oxidizing agent, it itself must be reduced, or put in other terms, it must be able to gain electrons. And for the record, the H2SO4 in order to react with Cu and to oxidize it, must be HOT and CONCENTRATED. Just putting Cu in some H2SO4 will not produce a reaction. The reaction of Cu + H2SO4 is as follows: Cu(s) + 2H2SO4(l) ---> Cu2SO4(s) + SO2(g) + 2H2O(g) ... note the states of each. In this reaction, the S of H2SO4 has gained electrons to form SO2, so it has been reduced and it has oxidized the Cu which went from Cu(s) to Cu^2+ in CuSO4. HCl is not capable of gaining electrons from Cu so it cannot oxidize the Cu.
Simply put: Yes. 2HCN + CuSO4 yields Cu(CN)2 + H2SO4
2NaOH + H2SO4 = Na2SO4 + 2H2O Ionic Equation 2Na + 2OH + 2H + SO4 = 2Na + SO4 + 2H2O Cross out common elements and compounds on both sides to get the ionic equation: 2OH + 2H = 2H2O
Cu+H2SO4 Gives CU2(SO4)2+H2O+S2O2
H, Mg, Zn, Cu
Oxidation number of h is 2
h
It is exothermic. Take for example H2SO4 H2SO4 -> H+ + HSO4- This is very exothermic