Pure HCl is 36.5 mwt so 0.5M would be 18.25 g pure HCl. In practice HCl is not pure but supplied at 36.5 % HCl typically.
It would be 0.1M HCl solution. In 1 liter there would be 3.65 g of HCl and the balance would be water.
There is no NaCl2. It would simply be NaCl and the reactant would be HCl and NaOH. Thus,HCl + NaOH ==> NaCl + H2O
Yes, water will completely dissolve HCl because HCl is a strong acid. The H+ ion is much less electronegative than the Cl- ion , so the Cl- ion pulls electrons towards itself in the chemical bond, and becomes very slightly negative. As a result, the H+ ion becomes slightly positive. Water is then able to "pull apart" the HCl because 0 is more electronegative than the Hs. The H+s from the HCl are attracted to the negative O of the water, and the Cl- from the HCl are attracted to the positive Hs of the water.
KCl
Pure HCl is 36.5 mwt so 0.5M would be 18.25 g pure HCl. In practice HCl is not pure but supplied at 36.5 % HCl typically.
It would be 0.1M HCl solution. In 1 liter there would be 3.65 g of HCl and the balance would be water.
There is no NaCl2. It would simply be NaCl and the reactant would be HCl and NaOH. Thus,HCl + NaOH ==> NaCl + H2O
((6100000/28.3495231250)/128)*1.50)=$2,521.54
Yes, HCl is a strong acid that completely dissociate and acetic acid is not
yeet
KCl
Yes, water will completely dissolve HCl because HCl is a strong acid. The H+ ion is much less electronegative than the Cl- ion , so the Cl- ion pulls electrons towards itself in the chemical bond, and becomes very slightly negative. As a result, the H+ ion becomes slightly positive. Water is then able to "pull apart" the HCl because 0 is more electronegative than the Hs. The H+s from the HCl are attracted to the negative O of the water, and the Cl- from the HCl are attracted to the positive Hs of the water.
When added to water, HCl would dissociate into H+ and Cl-. The H+ would form with water to make H3O+, increasing the pH of the substance.
First get moles HCl, then get the grams HCl.Molarity = moles of solute/Liters of solution3.8 M HCl = X moles/17.2 Liters= 65.36 moles HCl===============so,65.36 moles HCl (36.458 grams/1 mole HCl)= 2382.89 grams HCl======================and,put this amount, 2382.89 grams, 65.36 moles HCl into the 17.2 liters of solution ( water, I suppose ) 2382.89 grams = 2.38 kilograms. I suppose you could weigh out the HCl in a flask of some sort.
it depends if it is on the reactant side or product side. BUTTT in this case, I am assuming HCL is a solid.which whether or not it is on the reactant or product side, there would be NO CHANGE.
Not entirely correct: The molecular weight of HCl is 36.46g/Mole therefore a 36% (w/w) solution would be 36g/100g H2O or 36g/100mL H2O or 360g/L dividing that out, an exact 36% soln of HCl would be 9.87M (or 9.87N). To make a 1L soln of 1M HCl from 9.87M HCl you add 101.28ml HCl @ 9.87M to 898.72ml H2O. In practice HCl is labeled 36-38% (w/w) and it is treated as 10M (10N), for an exact measurement one must do a titration for the Cl ion. Add 85ml of 36w/w HCl to 900 ml of water,mix dilute to 1000ml with water,to get 1M HCl