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First get moles HCl, then get the grams HCl.

Molarity = moles of solute/Liters of solution

3.8 M HCl = X moles/17.2 Liters

= 65.36 moles HCl

===============so,

65.36 moles HCl (36.458 grams/1 mole HCl)

= 2382.89 grams HCl

======================and,

put this amount, 2382.89 grams, 65.36 moles HCl into the 17.2 liters of solution ( water, I suppose ) 2382.89 grams = 2.38 kilograms. I suppose you could weigh out the HCl in a flask of some sort.

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Q: How would you prepare 17.2 L of a 3.8 M HCl solution?
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