First get moles HCl, then get the grams HCl.
Molarity = moles of solute/Liters of solution
3.8 M HCl = X moles/17.2 Liters
= 65.36 moles HCl
===============so,
65.36 moles HCl (36.458 grams/1 mole HCl)
= 2382.89 grams HCl
======================and,
put this amount, 2382.89 grams, 65.36 moles HCl into the 17.2 liters of solution ( water, I suppose ) 2382.89 grams = 2.38 kilograms. I suppose you could weigh out the HCl in a flask of some sort.
You could titrate equal volumes of 1M solution of NaOH and 1M solution of HCl to obtain 1M solution of NaCl.
The answer is 15,039 g hydrogen chloride (HCl).
2 moles of HCl for every liter of solution.
100 M HCl don't exist.
Acid solutions are typically made in laboratories from commercially available acids which are supplied with specifications as to their physical and chemical properties including their concentrations. Calculations: For example, if you wish to use concentrated HCl that just arrived in your lab yesterday to make (say) 1N HCl, you will need to know the normality of the available solution. Suppose you know that it is 37% HCl (and all other information is missing); this means 37 mL HCl in 100 mL solution, M.W. of HCl = 36.5, Density = 1.185; 1.185 g HCl occupies 1 mL volume, 37 mL HCl corresponds to 43.84 g HCl. If the commercially available solution is 43.84 g HCl in 100 mL solution and you know that 36.5 g HCl in 1000 mL solution makes 1N (also 1M HCl) solution, then you have a 12N (also 12M) solution in your hands. So that means you must dilute it 12 times to get a 1N HCl solution. Titration: If you don't have a new solution at hand and are not sure about how correctly the HCl reagent was stored over many years, it would be prudent to measure the concentration of acid by titration provided you have fresh (reliable) base solutions at hand and reliable indicators.
Yes, it is possible to prepare oxalic acid by adding hcl to a solution og sodum oxalate. The balance equation would be C2O4Na2 + 2HCl -----> 2NaCl + C2O4H2.
Image result for You prepare a less concentrated H C l solution from a stock solution with 12m concentration. If you too 100g of the stock solution to prepare 4 MHCl solution how much water is needed to prepare o find solution 9density HCL(12) = 1,89/ml? The concentration would be 0.76 mol/L.
6g Tris HCl + 100ml dH2O, pH 6.8
520 ml of HCl in 480 ml of water=1000ml = 5 N
Prepare HCl 1 M by HCl concentration 37 % HCl concentration 37 % have density =1.19 g/ml HCl 1 M use HCl 37 % 82.81 ml make volume with water to 1 liter
25 mL
1.21 g Tris-HCl, QS water to 1L. Scale appropriately.
Mix approx. 12 mL of HCl 30 % in 1 L water.
dilute your HCl solution to 0.2 M HCl solution and then follow above mentioned link : http://delloyd.50megs.com/moreinfo/buffers2.html
add 5 ml of 37% HCl to 495 ml Water. This is 0.12 N ;)
44.5 ml HCl TAKE AND DILUTE UP TO 1000 ML WATER MAKE A 0.5 M HCl SOLUTION
You could titrate equal volumes of 1M solution of NaOH and 1M solution of HCl to obtain 1M solution of NaCl.