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import java.io.*;
class stack
{
char stack1[]=new char[20];
int top;
void push(char ch)
{
top++;
stack1[top]=ch;
}
char pop()
{
char ch;
ch=stack1[top];
top--;
return ch;
}
int pre(char ch)
{
switch(ch)
{
case '-':return 1;
case '+':return 1;
case '*':return 2;
case '/':return 2;
}
return 0;
}
boolean operator(char ch)
{
if(ch=='/'ch=='*'ch=='+'ch=='-')
return true;
else
return false;
}
boolean isAlpha(char ch)
{
if(ch>='a'&&ch<='z'ch>='0'&&ch=='9')
return true;
else
return false;
}
void postfix(String str)
{
char output[]=new char[str.length()];
char ch;
int p=0,i;
for(i=0;i{
ch=str.charAt(i);
if(ch=='(')
{
push(ch);
}
else if(isAlpha(ch))
{
output[p++]=ch;
}
else if(operator(ch))
{
if(stack1[top]==0(pre(ch)>pre(stack1[top]))stack1[top]=='(')
{
push(ch);
}
}
else if(pre(ch)<=pre(stack1[top]))
{
output[p++]=pop();
push(ch);
}
else if(ch=='(')
{
while((ch=pop())!='(')
{
output[p++]=ch;
}
}
}
while(top!=0)
{
output[p++]=pop();
}
for(int j=0;j{
System.out.print(output[j]);
}
}
}

The main class in another notepad

import java.io.*;
class intopost
{
public static void main(String args[])throws Exception
{
String s;
BufferedReader br=new BufferedReader(new InputStreamReader(System.in));
stack b=new stack();
System.out.println("Enter input string");
s=br.readLine();
System.out.println("Input String:"+s);
System.out.println("Output String:");
b.postfix(s);
}
}

OUTPUT: Enter input string
a+b*c
Input String:a+b*c
Output String:
abc*+

Enter input string
a+(b*c)/d
Input String:a+(b*c)/d
Output String:
abc*d/)(+

Enter

abc*d

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Q: Write a java program that accept stack ADT converts infix expression to postfix form evaluates the postfix expression?
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Why do compilers convert infix expressions to postfix?

people almost exclusively use infix notation to write mathematical expressions, computer languages almost exclusively allow programmers to use infix notation. However, if a compiler allowed infix expressions into the binary code used in the compiled version of a program, the resulting code would be larger than needed and very inefficient. Because of this, compilers convert infix expressions into postfix notation expressions, which have a much simpler set of rules for expression evaluation. Postfix notation gets its name from the fact that operators in a postfix expression follow the operands that they specify an operation on. Here are some examples of equivalent infix and postfix expressions Infix Notation Postfix Notation 2 + 3 2 3 + 2 + 3 * 6 3 6 * 2 + (2 + 3) * 6 2 3 + 6 * A / (B * C) + D * E - A - C A B C * / D E * + A C * - Where as infix notation expressions need a long list or rules for evaluation, postfix expressions need very few.


What is the method used to implement an if else statement in C?

The else statement is an optional part of an if statement that is executed if the primary if condition is false.if (condition) true_statementelse false_statement


Example program of how to convert infix notation to postfix notation and prefix notation?

/**************************//**********cReDo**********//*****mchinmay@live.com***///C PROGRAM TO CONVERT GIVEN VALID INFIX EXPRESSION INTO POSTFIX EXPRESSION USING STACKS.#include#include#include#define MAX 20char stack[MAX];int top=-1;char pop();void push(char item);int prcd(char symbol){switch(symbol){case '+':case '-':return 2;break;case '*':case '/':return 4;break;case '^':case '$':return 6;break;case '(':case ')':case '#':return 1;break;}}int isoperator(char symbol){switch(symbol){case '+':case '-':case '*':case '/':case '^':case '$':case '(':case ')':return 1;break;default:return 0;}}void convertip(char infix[],char postfix[]){int i,symbol,j=0;stack[++top]='#';for(i=0;iprcd(stack[top]))push(symbol);else{while(prcd(symbol)


Algorithm to convert postfix notation into infix notation?

/**************************//**********cReDo**********//*****mchinmay@live.com***///C PROGRAM TO CONVERT GIVEN VALID INFIX EXPRESSION INTO POSTFIX EXPRESSION USING STACKS.#include#include#include#define MAX 20char stack[MAX];int top=-1;char pop();void push(char item);int prcd(char symbol){switch(symbol){case '+':case '-':return 2;break;case '*':case '/':return 4;break;case '^':case '$':return 6;break;case '(':case ')':case '#':return 1;break;}}int isoperator(char symbol){switch(symbol){case '+':case '-':case '*':case '/':case '^':case '$':case '(':case ')':return 1;break;default:return 0;}}void convertip(char infix[],char postfix[]){int i,symbol,j=0;stack[++top]='#';for(i=0;iprcd(stack[top]))push(symbol);else{while(prcd(symbol)


An assembler converts source program into?

An Assembler converts an assembly language source code into machine-specific code.

Related questions

Sample program of postfix to infix?

You can convert from postfix to infix through the use of stacks. Consider the following expression conversion:54+67*+ -> ((5+4)+(6*7))The way this can be achieved is that whenever you encounter an operator, pop the last two expressions and join them using the operator. Remember to include the open braces before the first expression and a close braces after the second expression. Check the given link below for the program:


C plus plus program using a stacks converting a postfix-infix?

Yes


Why do compilers convert infix expressions to postfix?

people almost exclusively use infix notation to write mathematical expressions, computer languages almost exclusively allow programmers to use infix notation. However, if a compiler allowed infix expressions into the binary code used in the compiled version of a program, the resulting code would be larger than needed and very inefficient. Because of this, compilers convert infix expressions into postfix notation expressions, which have a much simpler set of rules for expression evaluation. Postfix notation gets its name from the fact that operators in a postfix expression follow the operands that they specify an operation on. Here are some examples of equivalent infix and postfix expressions Infix Notation Postfix Notation 2 + 3 2 3 + 2 + 3 * 6 3 6 * 2 + (2 + 3) * 6 2 3 + 6 * A / (B * C) + D * E - A - C A B C * / D E * + A C * - Where as infix notation expressions need a long list or rules for evaluation, postfix expressions need very few.


What is the method used to implement an if else statement in C?

The else statement is an optional part of an if statement that is executed if the primary if condition is false.if (condition) true_statementelse false_statement


Example program of how to convert infix notation to postfix notation and prefix notation?

/**************************//**********cReDo**********//*****mchinmay@live.com***///C PROGRAM TO CONVERT GIVEN VALID INFIX EXPRESSION INTO POSTFIX EXPRESSION USING STACKS.#include#include#include#define MAX 20char stack[MAX];int top=-1;char pop();void push(char item);int prcd(char symbol){switch(symbol){case '+':case '-':return 2;break;case '*':case '/':return 4;break;case '^':case '$':return 6;break;case '(':case ')':case '#':return 1;break;}}int isoperator(char symbol){switch(symbol){case '+':case '-':case '*':case '/':case '^':case '$':case '(':case ')':return 1;break;default:return 0;}}void convertip(char infix[],char postfix[]){int i,symbol,j=0;stack[++top]='#';for(i=0;iprcd(stack[top]))push(symbol);else{while(prcd(symbol)


What translation programs converts assembly language programs to object program?

The only translation program that converts assembly language to machine code is an assembler.


What is the program that reads and converts the entire program into object code called?

A compiler.


What is a c plus plus program that accepts a mathematical expression from a user and converts it to postfix expression and evaluates the result?

#include &lt;iostream&gt; #include &lt;cstdlib&gt; #include &lt;cstring&gt; #include &lt;cstdio&gt; #define size 400 using namespace std; char infix[size]="\0",postfix[size]="\0",Stack[size]; int top; int precedence(char ch) { switch(ch) { case '^':return 5; case '/':return 4; case '*':return 4; case '+':return 3; case '-':return 3; default:return 0; } } char Pop() { char ret; if(top!=-1) { ret=Stack[top]; top--; return ret; } else return '#'; } char Topelem() { char ch; if(top!=-1) ch=Stack[top]; else ch='#'; return ch; } void Push(char ch) { if(top!=size-1) { top++; Stack[top]=ch; } } int braces(char* s) { int l,r; l=0;r=0; for(int i=0;s[i];i++) { if(s[i]=='(') l++; if(s[i]==')') r++; } if(l==r) return 0; else if(l&lt;r) return 1; else return -1; } int main() { char ele,elem,st[2]; int T,prep,pre,popped,j=0,chk=0; cin&gt;&gt;T; while(T--) { j=0;chk=0;top=-1; strcpy(postfix," "); cin&gt;&gt;infix; chk=braces(infix); if(chk==0) { for(int i=0;infix[i];i++) { if(infix[i]=='(') { elem=infix[i]; Push(elem); } else if(infix[i]==')') { while((popped=Pop())!='(') { postfix[j++]=popped; } } else if(infix[i]=='^'infix[i]=='/'infix[i]=='*'infix[i]=='+'infix[i]=='-') { elem=infix[i]; pre=precedence(elem); ele=Topelem(); prep=precedence(ele); if(pre&gt;prep) Push(elem); else { while(prep&gt;=pre) { if(ele=='#') break; popped=Pop(); ele=Topelem(); postfix[j++]=popped; prep=precedence(ele); } Push(elem); } } else { postfix[j++]=infix[i]; } } while((popped=Pop())!='#') postfix[j++]=popped; postfix[j]='\0'; cout&lt;&lt;postfix; } } }


Algorithm to convert postfix notation into infix notation?

/**************************//**********cReDo**********//*****mchinmay@live.com***///C PROGRAM TO CONVERT GIVEN VALID INFIX EXPRESSION INTO POSTFIX EXPRESSION USING STACKS.#include#include#include#define MAX 20char stack[MAX];int top=-1;char pop();void push(char item);int prcd(char symbol){switch(symbol){case '+':case '-':return 2;break;case '*':case '/':return 4;break;case '^':case '$':return 6;break;case '(':case ')':case '#':return 1;break;}}int isoperator(char symbol){switch(symbol){case '+':case '-':case '*':case '/':case '^':case '$':case '(':case ')':return 1;break;default:return 0;}}void convertip(char infix[],char postfix[]){int i,symbol,j=0;stack[++top]='#';for(i=0;iprcd(stack[top]))push(symbol);else{while(prcd(symbol)


An assembler converts source program into?

An Assembler converts an assembly language source code into machine-specific code.


A computer program that converts an entire program into machine language at one time is called?

A compiler.


A computer program that converts the entire program into machine language at one time is called?

compiler