#include <stdio.h>
int main (void)
{
int i,j;
for (i=1;i<5;i++)
{
for(j=1;j<=i;j++)
printf("%d",j);
printf("\n");
}
return 0;
}
public class BubbleSortAscendingOrderDemo { public static void main(String a[]) { //Numbers which need to be sorted int numbers[] = {23,5,23,1,7,12,3,34,0}; //Displaying the numbers before sorting System.out.print("Before sorting, numbers are "); for(int i = 0; i < numbers.length; i++) { System.out.print(numbers[i]+" "); } System.out.println(); //Sorting in ascending order using bubble sort bubbleSortInAscendingOrder(numbers); //Displaying the numbers after sorting System.out.print("Before sorting, numbers are "); for(int i = 0; i < numbers.length; i++) { System.out.print(numbers[i]+" "); } }
A "do while....." statement is a looping instruction to a program to repeat a stage in the program while some condition is true - e.g while a variable is negative, or, while one variable is less than another. A "do for ....." statement is a looping instruction to a program to repeat a stage in the program a set number of times - e.g for steps = 1 to 10, or, for steps = 1 to (some variable).
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This is happening because when the programmer is displaying the number, it is being displayed as a character with a decoding process of a = 1, b = 2, etc. 5 + 8 = 13 = m
An infinite loop might look something like: while 1==1: print("Infinite loop") as 1 is ALWAYS equal to 1.
You cannot, unless n is a counter in a program or algorithm for a looping process. In that case, you need to know what the algorithm is doing.
for (n=1; n<1000; ++n) { for (sum=0, k=1; k<=n/2; ++k) if (n%k==0) sum += k; if (sum==n) printf ("%d\n", n); }
A program which is used to count the number of numbers in an array using a 8085 microprocessor is known as a assembly language program.
program to find maximum of two numbers using pointers
Use a looping structure. The first step initialises a loop control variable, n, to zero. You then begin the loop by processing the nth element from the array (the process may be a simple print statement). You then increment n. Finally, you test the value of n; if it is less than 10 you start a new iteration of the loop, otherwise you proceed to the end of the flowchart.