There are two functions in ctype.h: toupper() and tolower(). First one to make character into upper case and the second one for making lower case.
Here is a small program converting inputted character into lower case:
#include
#include
int main() {
char ch;
printf("Enter the char: ");
scanf("%c", &ch);
printf("Char in lowercase: %c\n", tolower(ch));
return 0;
}
Testing:
Enter the char: G
Char in lowercase: g
Enter the char: S
Char in lowercase: s
#include <ctype.h>
StringToUpper (char *psz) {
while (*psz != '\0') {
*psz = toupper (*psz);
psz++
}
}
StringToLower (char *psz) {
while (*psz != '\0') {
*psz = tolower (*psz);
psz++
}
}
This sounds like homework, and doing it all for you would not help you in the long run. But here are a few pointers.
System.out.println("text"); or System.out.print("text"); Please note that Java is case sensitive, meaning you must match uppercase and lowercase exactly.
write a program that reads a phrase and prints the number of lowercase latters in it using a function for counting? in C program
You first learn how to program in C.
/* my second program in C++ with more comments */ #include <iostream> using namespace std; int main () { cout << "Hello World! "; // prints Hello World! cout << "I'm a C++ program"; // prints I'm a C++ program return 0; }
In order to find whether a character in a string is in uppercase or not, you need to use the ascii\unicode values of the character. You may want to use the following code-- String str="Your Sample String Here"; //(say you have this string) int l=str.length(); for(int i=0;i<l;i++) { char ch=str.charAt(i); if(ch>=65&&ch<=90) //Since the values of block letters in ASCII are from 65 to 90 System.out.println(ch); } //This program basically prints out the block letters, but you can modify it as you like, by changing the statement after 'if' as you want
ten
System.out.println("text"); or System.out.print("text"); Please note that Java is case sensitive, meaning you must match uppercase and lowercase exactly.
write a program that reads a phrase and prints the number of lowercase latters in it using a function for counting? in C program
any body can help on this ?
A restaurant prints it out using a special program
You first learn how to program in C.
/* my second program in C++ with more comments */ #include <iostream> using namespace std; int main () { cout << "Hello World! "; // prints Hello World! cout << "I'm a C++ program"; // prints I'm a C++ program return 0; }
In order to find whether a character in a string is in uppercase or not, you need to use the ascii\unicode values of the character. You may want to use the following code-- String str="Your Sample String Here"; //(say you have this string) int l=str.length(); for(int i=0;i<l;i++) { char ch=str.charAt(i); if(ch>=65&&ch<=90) //Since the values of block letters in ASCII are from 65 to 90 System.out.println(ch); } //This program basically prints out the block letters, but you can modify it as you like, by changing the statement after 'if' as you want
reymond rillera reymond rillera
Your program is wrong.
Turbo Pascal is a style of computer programming. This type of writing language can be used to create a program that prints the alphabet backwards.
write a program that reads in the size of the side of square and then pints a hollow square of that size out of asterisks and blanks?