Write a program to accept two string and display weather they are identical or not?

Answer 1

I assume the program should be case-sensitive. Here is a code of such program:

#include

#include

int main() {

char str1[100];

char str2[100];

printf("Please enter first string: ");

gets(str1);

printf("Please enter second string: ");

gets(str2);

if (strcmp(str1, str2) == 0) {

printf("Strings are Equal.\n");

} else {

printf("Strings are Not Equal.\n");

}

return 0;

}

Testing:

Please enter first string: A

Please enter second string: A

Strings are Equal.

Please enter first string: a

Please enter second string: A

Strings are Not Equal.

If you want to make not case-sensitive comparing before checking you should make both string in lowercase or uppercase.

Here is how it should look:

#include

#include

#include

void upString(char *str);

int main() {

char str1[100];

char str2[100];

printf("Please enter first string: ");

gets(str1);

printf("Please enter second string: ");

gets(str2);

upString(str1);

upString(str2);

if (strcmp(str1, str2) == 0) {

printf("Strings are Equal.\n");

} else {

printf("Strings are Not Equal.\n");

}

return 0;

}

void upString(char *str) {

register int ind = 0;

while (str[ind]) {

str[ind] = toupper(str[ind]);

ind++;

}

}

Testing:

Please enter first string: aaa

Please enter second string: AAA

Strings are Equal.

Please enter first string: aaa

Please enter second string: aAa

Strings are Equal.

Note: You should not be using gets() function in real-world application. There is no way you can limit number of characters to read thus allowing to overflow buffer. It was used only for example.

Answer 2

The core of the program is:

if (strcmp (s1, s2)==0) puts ("They are equals");