Write a program to print n natural numbers using do-while loop?

Answer 1

//(this is just a function, call this as count(n) in your main loop)

void count(int n){

int i = 1;

do{

printf("%d", i);

i++;

} while(i<=n);

}

Answer 2

$n = 1;

do{

echo "$n\n";

}while(++$n <= 10);

Answer 3

int i=0;

do {

/*...*/

} while (++i<n);

Answer 4

void NNatural (int N) {

int n = 1;

do printf ("%d\n", n);

while (++n < N);

}