the gas is nitrogoen! xx :)
There is no reaction between lead nitrate and sodium nitrate, because both compounds contain the same anion (nitrate). The reaction, if written, would look like this...Pb(NO3)2 + NaNO3 ==> NaNO3 + Pb(NO3)2
The reaction between lead(II) nitrate and sodium iodide is a double replacement reaction. The products of this reaction are lead(II) iodide and sodium nitrate, formed through the exchange of ions.
Lead nitrate and potassium bromide react to form lead(II) bromide and potassium nitrate. This chemical reaction is a double displacement reaction where the cations and anions exchange partners to form the new compounds.
When lead(II) nitrate and sodium sulfate react, lead(II) sulfate and sodium nitrate are formed through a double displacement reaction. The balanced chemical equation for this reaction is: Pb(NO3)2 + Na2SO4 → PbSO4 + 2NaNO3. Lead(II) sulfate is a precipitate that appears as a white solid when this reaction occurs.
The dissolution reaction for lead(II) nitrate, Pb(NO₃)₂, in water can be represented as follows: [ \text{Pb(NO}_3\text{)}_2 (s) \rightarrow \text{Pb}^{2+} (aq) + 2 \text{NO}_3^{-} (aq) ] In this reaction, solid lead(II) nitrate dissociates into lead ions (Pb²⁺) and two nitrate ions (NO₃⁻) when it dissolves in water.
When potassium iodide reacts with lead nitrate, a double displacement reaction occurs. The potassium ion and the lead ion switch places to form potassium nitrate and lead iodide. This reaction results in the formation of a yellow precipitate of lead iodide.
No, they will not because their anions are same i.e. Nitrate
Silver nitrate and lead nitrate do not react, so there would be no precipitate.
When lead (II) nitrate and potassium sulfate are mixed, they will undergo a double displacement reaction. The products of this reaction are lead (II) sulfate and potassium nitrate. This can be represented by the chemical equation: Pb(NO3)2 + K2SO4 -> PbSO4 + 2KNO3.
The formula for lead (II) nitrate is Pb(NO3)2.
A thermally decomposition of the nitrate; the final products are lead oxide and nitrogen dioxide.
This is a double displacement reaction.