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1.26 mol of AlCl3

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Q: You are given 34.0 g of aluminum and 39.0 g of chlorine gas. If you had excess chlorine how many moles of aluminum chloride could be produced from 34.0 g of aluminum?
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When 4 moles of aluminum are allowed to react with an excess of chlorine gas Cl2 how many moles of aluminum chloride are produced?

4 moles


When 4 moles of aluminum are allowed to react with an excess of chlorine gas how many moles of aluminum chloride are produced?

Four:2 Al + 3 Cl2 --> 2 AlCl3so: 4 Al + 6 Cl2 --> 4 AlCl3


When 4 moles of aluminum are allowed to react with an excess of chlorine gas CL2 how many moles of aluminum chlorde are produced?

4 moles


When 0.440 mol of aluminum are allowed to react with an excess of chlorine gas Cl2 how many moles of aluminum chloride are produced?

Equation. 2Al + 3Cl2 -> 2AlCl3 one to one again 0.440 moles Al (2 moles AlCl3/2 moles Al) = 0.440 moles AlCl3 produced


How many grams of aluminum chloride are produced when 18 grams of aluminum are reacted with an excess of hydrochloride acid?

The empirical formula for aluminum chloride is AlCl3, and its gram formula mass is 133.34. The formula shows that each formula unit contains one aluminum atom, and the the gram atomic mass of aluminum is 26.9815. Therefore, 18(133.34/26.9815) or 89 grams, to the justified number of significant digits, of aluminum chloride will be produced.


If you start with 3.52g aluminum and 5.03 g of chlorine with the the excess reactant and how much is in the excess?

We need 6,935 g aluminium; the excess of aluminium is 0,97 g.


What mass of sodium chloride is produced if 92.0 of sodium reacts with excess Chlorine?

Sodium has an atomic weight of 22.99 g/mol. Chlorine has an atomic weight of 35.45 g/mol. NaCl has an atomic weight of 58.44 g/mol. Therefore 92g of sodium would yield 233.86g of sodium chloride (NaCl).


When 10.0 grams of calcium reacts with 20.0 grams of chlorine gas, how many grams of calcium chloride can be produced Which reactant is in excess and which is the limiting reactant?

The balanced chemical equation for the reaction between calcium and chlorine gas to produce calcium chloride is: Ca + Cl2 -> CaCl2. From this equation, we can see that one mole of calcium reacts with one mole of chlorine gas to produce one mole of calcium chloride. The molar mass of calcium is 40.08 g/mol and the molar mass of chlorine gas is 70.90 g/mol. This means that 10.0 grams of calcium is equivalent to 0.249 moles of calcium and 20.0 grams of chlorine gas is equivalent to 0.282 moles of chlorine gas. Since the ratio of calcium to chlorine gas in the balanced chemical equation is 1:1, this means that 0.249 moles of calcium would react completely with 0.249 moles of chlorine gas, leaving an excess of 0.033 moles (or 2.34 grams) of chlorine gas. The limiting reactant in this reaction is calcium, and the maximum amount of calcium chloride that can be produced is equivalent to the number of moles of the limiting reactant, which is 0.249 moles (or 27.8 grams) of calcium chloride.


In the reaction of silver nitrate with sodium chloride how many grams of silver chloride will be produced from 100 g of silver nitrate when it is mixed with an excess of sodium chloride?

58.9g


How many grams of aluminum chloride can be made from 67.0 grams of aluminium and excess hydrochloric acid?

The answer is: approx. 327 g.


How many grams of carbon tetrachloride can be produced from reacting 709.0 grams of chlorine with excess methane?

384.5g


Why is aluminum chloride used in large excess in Friedel-Crafts reactions?

To ensure there's enough of it to allow the reaction to go to completion.