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Q: How many grams are in 0.155 mole of sulfur?
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How many grams in a mole of sulfur?

1 mole of sulfur contains 32.065g of sulfur.Source: Periodic table of elements.


6.11 mole of sulfur trioxide have a mass of how many grams?

Sulfur Trioxide has a molar mass of 80.0632 grams per mole. Therefore, 6.11 moles of Sulfur Trioxide is 489.186152 grams (without significant figures). With significant figures that would be 489 grams.


How many atoms of sulfur are in a 48.0 g chunk of sulfur?

48.0 grams sulfur (1 mole S/32.07 grams)(6.022 X 10^23/1 mole S) = 9.01 X 10^23 atoms of sulfur


How many atoms are there in 72.0 g of sulfur?

72.0 grams sulfur (1 mole S/32.07 grams)(6.022 X 10^23/1 mole S) = 1.35 X 10^24 atoms of sulfur


How many moles of atoms are there in 48.096 grams of sulfur?

Full formal set up. 48.096 grams sulfur (1 mole S/32.07 grams)(6.022 X 1023/1 mole S)(1 mole S atoms/6.022 X 1023) = 1.4997 moles of sulfur atoms ---------------------------------------


What is the weight of one mole of sulfur?

The molecular weight of 1 mole of sulfur is 32 amu or grams.


How many moles OF s are present 7.71g of s?

7.71 grams sulfur (1 mole S/32.07 grams) = 0.2404 moles of sulfur


How many atoms does g of sulfur contain?

Just about 6.022 X 1023 atoms of sulfur. Sulfur is 32.07 grams per mole.


How many atoms are in 64 g S?

64 grams sulfur (1 mole S/32.07 grams)(6.022 X 1023/1 mole S) = 1.2 X 1024 atoms of sulfur ====================


What is Mass of one mole of sulfur?

It is 32.06 grams.


How many atoms does 32 g sulfur contain?

Just about 6.022 X 1023 atoms of sulfur. Sulfur is 32.07 grams per mole.


How many atoms 32 g of sulfur contain?

Just about 6.022 X 1023 atoms of sulfur. Sulfur is 32.07 grams per mole.