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Use of a diode across a DC electromagnetic device, such as a valve, is to counter the reverse voltage (EMF) caused by the collapse of the magnetic field when the power is turned off. If the diode were not present, the reverse voltage can become very large, even to thousands of volts or more, and it can damage the associated circuitry.
In this application, the anode is connected to the negative side, and the cathode is connected to the positive side. When power is applied, the diode does not conduct. When power is removed, and the inductor attempts to maintain the current flow by generating a reverse voltage, the diode conducts until the magnetic field collapses.
What else can I help you with?
Why diode dose not allow to set voltage more than 0.7volts across it?
The barrier potential of the silicon diode is 0.7v if the applied voltage across it is more than this voltage then PN-junction of the diode breaks, once pn-junction breaks the voltage across the diode is constant, since it breaks at 0.7 this voltage will be constant and not exceed for any further increase in applied voltage -inform.mayaprasad@gmail.com The voltage across junction will only exceed from 0.7 volt (for silicon diode) in the case of reverse biasing the applied total voltage will appear across p-n junction. ANSWER: .7 VOLTS is an arbitrarily chosen number since a diode any diode have an exponential curve V vs I . This number is chosen when using a diodes but there are times when a greater or lesser voltage is chosen to reflect the application and the current trough the diode determine that. Example a diode gate diode will be chosen as .6 volts rather then .7v and a heavy conducting rectifier may have .8 volt to reflect closely the true value of the diode drop during real conditions
Is forward voltage drop of schottky diode more than tunnel diode?
Yes, the forward voltage drop of a Schottky diode is usually more than the forward voltage drop of a tunnel diode. A Schottky diode voltage drop is between approximately 0.15 to 0.45 volt. The interesting thing that makes a tunnel diode different from other diodes is its "negative resistance region" with a "peak current" around 0.06 volt and a "valley current" around 0.30 volt.
IN5408 diode what does it do?
The IN5408 diode is an ordinary silicon diode. It has a 3 amp forward current rating, and a 1000 volt peak reverse voltage rating.
What will happen if the supply voltage polarity is reveresed for the case of using a diode with piv of 4.8 volt?
If we give more than 4.8 volt to a diode in reverse bias condition it will break down or destroyed.
How do you connect a volt to a circuit?
A volt can not be connected to a circuit.
How do you connect several 12 volt batteries to make 24 volt?
you only need two 12 volt batteries to make 24 volt. connect them in series
How do I connect a twelve volt car battery to two six volt batteries connected in a series?
connect the 2 six-volt batteries together one terminal each positive to negitive, this will make a 12-volt combination, then you can connect the jumper cables, one side to the 12-volt battery and one side to the two 6-volt terminals, + & -
How do you get 12 volt output from 2x 12 volt batts how to setup the leads?
connect + to + and - to - and connect the load between the two + and the two -
How do you connect six 6-volt cart batteries?
Connect them in series.
Volt ampere equation for a pn diode?
I=I0 (exp(V/(ita)VT -1)
What is the voltage drop per led in a 25 led series circuit with 120 volt supply and leds are 3.0 volts 20 ma with a resistor of 5000 ohms?
There is not enough information to answer this question correctly. As the current increases through a diode, the voltage dropped across it increases. This correlation is not a linear function such as a resistance, and a datasheet for the diode or a curve tracer would be necessary to obtain the correct function. To explain further, if there were 25 series LEDs all with a 3 volt drop across them, a 75 volt potential would be measured across the diodes, and 45 volts would be measured across the 5000 ohm resistor. Ohms law will show that 45 volts applied to 5K ohms will equal 9mA. This violates the 20mA criteria in the question.
How do you find voltage rating of zener diode?
It should be marked, either on the diode or on the box it came in. If you can't find the mark, then you have to measure it yourself. Take the zener diode, a battery or DC power supply, and a resistor. Wire them all in series, with the NEG (cathode) end of the diode closer to the POSitive side of the battery or power supply. Connect your voltmeter across the diode, and slowlyincrease the power supply output voltage while watching the meter. You'll see the voltage across the diode increase slowly, tracking the power supply, until you reach the Zener voltage. At that point, the voltage across the diode won't increase any more; it'll just stay there at its 'reverse breakdown' voltage, which is the Zener voltage. (If the voltage across the diode goes to around a volt and won't go any higher, the polarity is wrong. Reverse either the diode or else the power supply.) You probably want a wild guess at what the value of the resistor should be. That's difficult to specify if I don't know the power rating of the Zener diode you're testing. I'm going to make the following suggestion completely in the blind: Select the resistor to limit the series current to 30 mA even if you have to crank the power supply up to 50 volts. R = 50/.03 = 1.5 to 2 K-ohms, rated for a couple of watts.
