Add another leg of 120 to a three pole breaker.
Current in 200kw at 480 volts = 200,000/480 = 416.667 amps
88 amps
The heater should have a wattage rating (very few list amps). Calculate the amps using the wattage and voltage. Amps = Watts/Volts(480).
If you have 208 between legs, you have 120 from each leg to neutral (208 divided by 1.73). Assuming a balanced load, this would be 1 KW per leg - 1000 divided by 120 = 8.33 amps per leg. Your question contradicts itself. If you have 208v, the answer above is correct, 8.33 amps. If you have 480v, you have 3.6 amps.
It is hard to see a question here. Both of these voltages are currently use in electrical systems today. Both voltages are related to three phase systems. A voltage of 208 volts is a three phase wye system that has a voltage of 208 between lines L1, L2 and L3 and 120 volts between any of the lines and neutral. A voltage of 277 is the line to neutral voltage of a 480 volt three phase wye system. There is a voltage of 480 between L1, L2 and L3 and 277 volts between any of the lines and neutral.
To calculate the amperage, you can use the formula: Amps = (kW × 1000) / (√3 × Volts). Plugging in the values, we get: Amps = (45 × 1000) / (√3 × 208) ≈ 131.1 amps. So, the hot water heater would draw approximately 131.1 amps.
It depends on the voltage: 208 v 14 amps, 415 v 7 amps, 480 v 6 amps.
200 and 100
You need to mention the Load connected to find the current.
It depends on your definition of efficiency. 480 can certainly push more power than 208 through the same size conductors, but it would not be efficient to wire a motor for 480 when 208 was all that was needed.
Your question answers itself... 1000 watts, when operated on a 480-volt source..
The volt drop on a cable 912 meters 480 volts and load of 54 amps is 5% if you use 2/0 AWG wire and 2.4% if you use 300MCM wire. See Related Links below