Anything to do with vaginas
The surface temperature of a star can be determined by analyzing its spectrum. Specifically, scientists can observe the peak wavelength of light emitted by the star and use Wien's Law, which relates the peak wavelength to the temperature of the emitting object. By measuring the peak wavelength, astronomers can calculate the surface temperature of the star.
The thermal radiation spectrum of an 8000 K star would peak at shorter wavelengths (bluer light) compared to a 4000 K star, which would peak at longer wavelengths (redder light). Additionally, the 8000 K star would emit more energy overall at all wavelengths compared to the 4000 K star due to the higher temperature leading to a higher luminosity.
Yes. The apparent colour of a star is related to the peak wavelength of the light it emits. According to Wien's displacement law (look it up in Wikipedia) the peak wavelength is inversely proportional to the temperature. The higher the temperature, the shorter the peak wavelength. Wavelength decreases as one moves from red to blue in the visible spectrum, so a red star is cooler than a blue one.
ultraviolet. Comment: I agree, or it could simply be blue in some cases.
The hottest star is of blue color. The more the heat , the more is the excitement of electrons in star. This electrons vibrate with high frequency and emits light. Since the frequency is high, it appears as of blue color
The star emitting the shortest wavelength of its peak frequency will be a star with high temperature, such as a blue star. This is because the wavelength of light emitted by an object is inversely proportional to its temperature according to Wien's law.
Measure the time for a wave to pass a given point- peak to peak. The number of complete peak-to-peak waves per second/minute is the frequency of that wave.
Rods have their peak sensitivity at a lower frequency compared to cones.
It's peak frequency
To determine the natural frequency from a graph, identify the peak point on the graph which represents the highest amplitude or resonance. The frequency corresponding to this peak point is the natural frequency of the system.
A: Take 115 volts and multiply by 2.82. The frequency does not matter but he voltage does
the amlitude of the input signal 10 volt peak to peak was set at 10 khz
buat lab ke?haha
Frequency 27500
The peak frequency of emitted light is directly proportional to the temperature of the incandescent source, as described by Wien's displacement law. As the temperature of the source increases, the peak frequency of the emitted light shifts to higher values, resulting in a bluer appearance for higher temperatures and a redder appearance for lower temperatures.
The peak frequency of radiant energy is directly proportional to the absolute temperature of the radiating source, as described by Wien's displacement law. As the temperature of the source increases, the peak frequency of the emitted radiation also increases. This means that hotter objects emit higher frequency (shorter wavelength) radiation.
Heat radiation, also known as thermal radiation, is emitted at various frequencies depending on the temperature of the object. As temperature increases, the frequency of the radiation also increases. The peak frequency of heat radiation is given by Wien's displacement law: f_peak = c / λ_peak, where f_peak is the peak frequency, c is the speed of light, and λ_peak is the peak wavelength.