Your simplest scheme would be to wire them in series - one after the other - thus presenting a 16 ohm load to the amplifier. This will cause no harm to the amplifier.
If you wired them in parallel, then the effective load would be only 4 ohms, and this would cause more load on the amplifier. Depending upon the design of your amplifier, this could cause more distortion.
In closing, it is only in the 'mid range' that the impedance of the speaker is the nominal load - say 8 ohm. At 'resonance' - generally at frequencies of a few tens of Hertz, the impedance of your speaker will be a few times its nominal impedance. At high frequencies, again the impedance of the speaker will increase to a few times nominal.
If you mean as pairs, yes. put an 8 Ohm and a 16 Ohm speaker in parallel for each channel. The 16 Ohm speakers will take 1/3 the power and the 8 Ohm speakers will take 2/3 the power. The resulting impedance will be 5.33 Ohms.
No that would be a 2 channel amp. 1 speaker per channel. 2 speakers= 2 channels 4 speakers= 4 channels
A 4 channel will work for your door speakers. But the idea setup would be a 5 channel 4 for your doors. Then have 1 channel for a sub.
Use 1 channel for fronts & the other channel for the rears.
To wire two 8-ohm speakers together while maintaining an 8-ohm total impedance, connect them in parallel. This means you should connect the positive terminals of both speakers together and the negative terminals together, then connect the paired terminals to your amplifier. The formula for calculating impedance in parallel is 1/R_total = 1/R1 + 1/R2; thus, two 8-ohm speakers in parallel result in a total impedance of 4 ohms. To stay at 8 ohms, you can wire one speaker in series with another 8-ohm speaker, resulting in a total impedance of 16 ohms or use a different configuration or additional speakers.
take the positive from speaker A and twist the copper wire together with the positive wire from speaker B. then take those two (positive) wires from A and B and put it in Channel 1 positive terminal. then take the negative from speaker A and twist the copper wire together with the negative wire from speaker B. take those two (negative) wires and put them in the negative terminal under channel 1. then do the same for your other 2 speakers, except in channel 2
Maybe.The real question comes down to the resistance of the output on the amp vs. the resistance of the speakers. You'll have to do a little math and understand the difference between series and parallel wiring. Throw back to high school physics.When you're wiring something in series the resistances are added. So, if you have two 8 ohm speakers the total resistance is 16 ohms. If the output resistance on the amp is 16 ohms, you're in good shape, but don't crank it or it definitely will blow.When you wire a parallel circuit you use the formula 1/RT=(1/R1)+(1/R2). Again, if both speakers are 8 ohms then it's 1/RT=(1/8)+(1/8). With a little math you get 4 ohms. This is WAAAAAAAY different from 16 ohms. Turn that 16 ohm amp on now and those speakers will turn into a fun light show, but they'll be toasted. Throw some butter on it and you've got breakfast.
In series like so ---6 ohms ---- 12 ohms --- , the total resistance is just 6 ohms + 12 ohms.assuming you mean in parallel like this:_|---6 ohms-----|-|~|-_|---12 ohms---|then the resistance of this can be calculated like so:1/6 ohms + 1/12 ohms = 1/R (where R is the resistance of the circuit as a whole)2/12 ohms + 1/12 ohms = 1/R3/12 ohms = 1/R1/4 ohms = 1/Rso R = 4 ohmsA few notes, if the resistors are in parallel the total resistance will always be less than or equal to the lowest resistance in parallel (i.e 6 ohms in parallel with 12 ohms will have resistance less than 6 ohms).Also if two resistances in parallel are the same, then the resistance is half of the resistance of both resistors (i.e. 1/2 ohms + 1/2 ohms = 1/R; 1 = 1/R, R=1 ohm which is half of 2 ohms).This process can be extended to 2 or more resistors in parallel.i.e if we had a 6 ohm, 6 ohm and 12 ohm resistor in parallel we could go1/6 ohms + 1/6 ohms + 1/12 ohms = 1/R(1/6 ohms + 1/6 ohms) + 1/12 ohms = 1/R1/3 ohms + 1/12 ohms = 1/R4/12ohms + 1/12 ohms = 1/R5/12 ohms = 1/Rso R = 12/5 ohms or 2.4 ohms
With Subwoofers only, you would want to go with only a 1 channel or 2 channel amp, 5 channel amps are designed to power 4 smaller speakers, and 1 subwoofer. Each channel basically refers to a different speaker - if you're using 2 regular left and right Speakers (not Subwoofers), use 2 channel setting, if you have 4 Speakers plus a subwoofer, use 5 channel setting. Make sure subwoofer is tested with the lowest gain/volume.
That should work fine...matching is not critical. However if you want to be "pure", you could: 1...Insert a 2 ohm resistor in series, but that reduces damping and you may get coil resonances. 2...Install a 2 ohm to 4 ohm transformer. Hard to find and expensive. 3...Install two speakers in series, remembering to phase them correctly.
Not really. The only possible configurations of four 4 ohm speakers is 1 ohm, 4 ohms, and 16 ohms. This will not match an 8 ohm rated amplifier. It will work, but you will not achieve rated power output, and you run the risk of damaging the amplifier.
The dash speakers on the left and right are 3 1/2" round speakers. I have no idea how big the center channel dash speaker is.