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If both parents were Dd then what would the phenotypic ratio be?
Moneymanmannie
Phenotypic ratio: 3 D, 1d [3 dominant, 1 recessive]
Genotypic ratio: 1DD, 2Dd, 1dd
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∙ 14y ago
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Two plants are crossed resulting in offspring with 3 to 1 ratio for a particular trait?
that the parents were true-breeding for contrasting traits. NOT TRUE. If so, all the offspring would be identical genotypes. Think of a classic cross that gives you a 3:1 ratio and write it out. It would suggest that the parents were both heterozygous for a single trait.
What is the phenotype ratio of F1 generation of peas?
9:3:3:1 was the ratio of Mendel's f2 generation for the two factor cross.
Two plants are crossed resulting in offspring with a 3 to1 ratio for a particular trait This suggests?
That the parents were both heterozygous!
How did Mendel figure out the law of independent assortment?
Mendel figured this out by following two characteristics at the same time. (dihyrid).As opposed to the law of segregation where he only followed one. (monohybrid).He crossed two true breeding varieties that differed in two characters.The F1 generation of these were both heterozygous displaying the dominant phenotype.By breeding these together there could have been two outcomes:1: the predicted offspring of the F2 generation would have a phenotypic ratio of 3:1, like the monohybrids, (meaning the inheritance of the two characters were dependent upon each other); or2: the predicted offspring of the F2 generation would have a phenotypic ratio of 9:3:3:1. Meaning the two characteristics were inherited independently.As it turned out the second was true for all his experiments. The numbers didn't lie.Consider the two traits in the following (Trait One: "Oo" and Trait Two "Tt"):P Generation:OOTT bred with oottGametes would be:OT and ot.F1 Generation:Both OoTtF2 Generation showing independent assortment:OOTT OOTt OoTT OoTtOOTt OOtt OoTt OottOoTT OoTt ooTT ooTtOoTt Ottt ooTt oottNote the phenotypic ratio: 9:3:3:1.This outcome would have not been displayed if the traits weren't assorted independently.
How do traits appear in the next generation?
Phenotypic traits are how certain, inherited genes are expressed.During reproduction, both the mother and father gives their child a chromosome, which often results in the child displaying traits similar to his/her parents'.
What is the phenotype of an individual heterozygous of both?
The phenotypic ratio would be 3 to 1
What is the phenotype of an individual heterozygous of both traits?
The phenotypic ratio would be 3 to 1
Why does the expected genotypic ratio often differ from the expected phenotypic ratio from monohybrid cross?
Because in heterozygotes, both alleles are transcribed and translated.
What is the importance of a 9331 ratio in a monohybrid cross?
The phenotypic ratio expected from a monohybrid cross between heterozygotes is 3:1 (assuming complete dominance), with the genotypic ratio being 1:2:1. So, using tall = T, short = t and R = red, r = white as an example. A monohybrid cross of Tt X Tt would be expected to produce 3 tall plants and 1 short plant (phenotypic ratio 3:1), which would be 1 TT, 2 Tt and 1 tt (genotypic ratio 1:2:1). A dihybrid cross of heterozygotes is expected to produce a phenotypic ratio of 9:3:3:1. So the cross of TtRr X TtRr would be epected to have: 9 tall red, 3 tall white, 3 short red and 1 short white (phenotypic ratio) This is because each parent has 4 possible combinations of gametes (TR, Tr, tR and tr). There are therefore 16 combinations of gametes, providing a 9:3:3:1 phenotypic ratio. Both of these are probably best visualised using a punnett square (see link below).
What phenotypic ratios are likely to occur in crosses when dealing with two completely dominant independently segregating gene pairs when both parents are fully heterozygous?
9:3:3:1
Two plants are crossed resulting in offspring with 3 to 1 ratio for a particular trait?
that the parents were true-breeding for contrasting traits. NOT TRUE. If so, all the offspring would be identical genotypes. Think of a classic cross that gives you a 3:1 ratio and write it out. It would suggest that the parents were both heterozygous for a single trait.
What are some of the phenotypic variations that are possible with codominance?
Blending or mixing of the colors is a phenotypic variation that is possible with co-dominance. Seeing both colors present at the same time is also possible.
What is the phenotype ratio of F1 generation of peas?
9:3:3:1 was the ratio of Mendel's f2 generation for the two factor cross.
Both parents a type what would siblings be?
If both of your parents have Type A blood, the blood of you and your siblings can be A or O.
How would a recessive trait show up in a cross between two individuals with a dominant phenotype?
If both the individuals are heterozygous dominant then the probability of recessive (homozygous) phenotypic offspring would be 1:4
Two plants are crossed resulting in offspring with a 3 to1 ratio for a particular trait This suggests?
That the parents were both heterozygous!
If both heterozygous parents are carriers of a recessive allele for phenylketonuria the probability that a given child of these parents will have PKU is?
Pp x Pp yields PP, Pp, Pp, pp. PP is the only genotype which will cause the phenotypic expression of the gene - symptoms of PKU. Therefore the probability is 1/4 or 25%
