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A cross between two pea plants that produce yellow seeds results in 124 offspring 93 produce yellow seeds and 31 produce green seeds what are the likely genotypes of the plants that were crossed?
The parents were likely both heterozygous for seed color, with genotypes of Yy. This would result in a 3:1 phenotypic ratio of yellow to green seeds in the offspring, consistent with the observed 93:31 ratio.
What is the phenotype ratio of F1 generation of peas?
9:3:3:1 was the ratio of Mendel's f2 generation for the two factor cross.
What is the phenotypic ratio of the following dihybrid cross AaBb x AaBb?
The phenotypic ratio of the cross AaBb x AaBb is 9:3:3:1, which represents the different possible combinations of genotypes for the offspring based on the principles of Mendelian genetics. This ratio indicates that 9 out of 16 offspring will exhibit the dominant phenotype for both traits, while 3 out of 16 will exhibit one dominant and one recessive phenotype, 3 out of 16 will exhibit the other dominant and recessive phenotype, and 1 out of 16 will exhibit both recessive phenotypes.
According to Mendel a cross between two round yellow peas both with the genotype RrYy would result in mostly peas?
Both round and yellow. This is because roundness (R) and yellowness (Y) are dominant traits and would mask the recessive traits for wrinkledness and greenness. The genotype RrYy results in a 9:3:3:1 phenotypic ratio of round yellow, round green, wrinkled yellow, and wrinkled green peas.
What is the phenotype ratio expected from crossing AaBb X AaBb?
The gametes would be AB, Ab, aB, ab which would go both across the top and down the side of the punnett square. The genotypic ratio is 1:2:1:2:4:2:1:2:1 1AABB: 2AABb: 1 AAbb: 2 AaBB: 4AaBb: 2Aabb: 1aaBB: 2aaBb: 1aabb The phenotypic ratio is 9:3:3:1 9AB: 3Ab:3aB:1ab phenotypes
What is the phenotype of an individual heterozygous of both?
The phenotypic ratio would be 3 to 1
What is the phenotype of an individual heterozygous of both traits?
The phenotypic ratio would be 3 to 1
What ratio would you expect in a two factor cross if both parents are heterozygous?
In a two-factor cross where both parents are heterozygous for two traits (e.g., AaBb x AaBb), you would expect a phenotypic ratio of 9:3:3:1 in the offspring. This ratio represents the combinations of the dominant and recessive traits for both factors. The 9 represents the offspring with both dominant traits, while the 3s represent the combinations with one dominant and one recessive trait, and the 1 represents the offspring with both recessive traits.
Why does the expected genotypic ratio often differ from the expected phenotypic ratio from monohybrid cross?
Because in heterozygotes, both alleles are transcribed and translated.
What is ratio for PHenotypic ration TT Tt TT Tt?
The phenotypic ratio for the given genotypes (TT, Tt, TT, Tt) can be determined by identifying the traits represented by these genotypes. In this case, both TT and Tt result in the dominant phenotype, while there are no recessive phenotypes present. Thus, the phenotypic ratio is 4:0, indicating that all offspring display the dominant trait.
What phenotypic ratios are likely to occur in crosses when dealing with two completely dominant independently segregating gene pairs when both parents are fully heterozygous?
In a cross involving two completely dominant independently segregating gene pairs with both parents fully heterozygous, the phenotypic ratio is typically 9:3:3:1. This is due to the random assortment of alleles during gamete formation and the combination of alleles in the offspring during fertilization that leads to the different phenotypic outcomes.
What is the phenotypic ratio of AaBb and aabb?
When AaBb is crossed with aabb, the resulting phenotypic ratio of the offspring can be determined by examining the possible combinations of alleles. The AaBb parent can produce gametes AB, Ab, aB, and ab, while the aabb parent can only produce ab. The phenotypic ratio of the offspring will be 1:1:1:1 for the combinations A_B_, A_bb, aaB_, and aabb, resulting in a total of 1 dominant for both traits, 1 dominant for the first trait and recessive for the second, 1 recessive for the first and dominant for the second, and 1 recessive for both traits. Thus, the phenotypic ratio is 1:1:1:1.
What is the phenotypic ratio of PpRr X Pprr?
To determine the phenotypic ratio of the cross PpRr (heterozygous for both traits) and Pprr (heterozygous for the first trait and homozygous recessive for the second), we can set up a Punnett square. The offspring will display four phenotypes based on dominant and recessive traits for both characteristics. The resulting ratio is 3:1 for the first trait (P vs. p) and 1:1 for the second trait (R vs. r), leading to a combined phenotypic ratio of 3:1:1:1 (3 dominant for the first trait and 1 recessive for both traits).
If you cross two hybrids what will be the ratio of it?
When you cross two hybrids, the ratio of the offspring typically depends on the genetic makeup of the hybrids and the traits being studied. For example, if both hybrids are heterozygous for a single trait (e.g., Aa x Aa), the expected phenotypic ratio in the offspring would be 3:1 for dominant to recessive traits. If the hybrids are heterozygous for two traits (e.g., AaBb x AaBb), the phenotypic ratio would be 9:3:3:1. Always consider the specific genetics involved for accurate predictions.
What is the importance of a 9331 ratio in a monohybrid cross?
The phenotypic ratio expected from a monohybrid cross between heterozygotes is 3:1 (assuming complete dominance), with the genotypic ratio being 1:2:1. So, using tall = T, short = t and R = red, r = white as an example. A monohybrid cross of Tt X Tt would be expected to produce 3 tall plants and 1 short plant (phenotypic ratio 3:1), which would be 1 TT, 2 Tt and 1 tt (genotypic ratio 1:2:1). A dihybrid cross of heterozygotes is expected to produce a phenotypic ratio of 9:3:3:1. So the cross of TtRr X TtRr would be epected to have: 9 tall red, 3 tall white, 3 short red and 1 short white (phenotypic ratio) This is because each parent has 4 possible combinations of gametes (TR, Tr, tR and tr). There are therefore 16 combinations of gametes, providing a 9:3:3:1 phenotypic ratio. Both of these are probably best visualised using a punnett square (see link below).
Why does the expected genotypic ratio differ from the expected phenotypic ratio?
The expected genotypic ratio differs from the expected phenotypic ratio because genotypes represent the actual genetic combinations (e.g., homozygous dominant, heterozygous, homozygous recessive), while phenotypes reflect the observable traits resulting from those genotypes. In cases where one allele is dominant over another, multiple genotypes can lead to the same phenotype. For example, in a monohybrid cross, the expected genotypic ratio might be 1:2:1 for the alleles, while the phenotypic ratio could be 3:1, as both homozygous dominant and heterozygous individuals display the same dominant phenotype.
A cross between two pea plants that produce yellow seeds results in 124 offspring 93 produce yellow seeds and 31 produce green seeds what are the likely genotypes of the plants that were crossed?
The parents were likely both heterozygous for seed color, with genotypes of Yy. This would result in a 3:1 phenotypic ratio of yellow to green seeds in the offspring, consistent with the observed 93:31 ratio.
