Yes, it is.
The Electrophilic Addition Reaction is when the attacking species during the addition reaction is"Electrophile", it is called "electrophilic addition reaction". Examine: (+) (-) (+) (-) (+) (-) CH2Br-CH2BràH2C-CH2+BrBr-àH2C=CH2+Br2-
many things cyanide, cyanide compounds, heavy metals, radioactive material, inert gases such as nitrogen causes asphixia, hydrogen sulphide, clorine, hydrogen chloride, phosphine, phosgene, bacteria or other living things may take up resources. Heaps more
a molecule of an elemnt has only one element in it[ duh!!] like for eg. oxygen is O2 and hydrogen is H2. a molecule of a compound has more than one element in it, for example water H2O, HCl , NaCl etc etc
Photo synthesis occurs when plants containing a pigment, chlorophyll traps the energy in the sun and uses the energy to create a chemical reaction. Then raw materials, carbon dioxide and water are combined to make sugar(glucose). The left over energy is then stored in a form of starch and carbohydrates, in the leaves, roots and stem. It then releases its main byproduct oxygen.-Zahaa Safodien
Yes, Br2 is an oxidizing agent.
Fluorine (F2) is the strongest oxidizing agent among the listed halogens. It has the highest electronegativity and is the most reactive due to its small atomic size, making it a powerful oxidizing agent.
The correct chemical equation for the reaction is: Cl2 + 2KBr → 2KCl + Br2. The reaction involves chlorine gas (Cl2) reacting with potassium bromide (KBr) to form potassium chloride (KCl) and bromine gas (Br2).
S in (SO4)-2 has a charge of +6, in SO2 S has a charge of +4. To go from +6 to +4 you must gain two electrons. The (SO4)-2 is reduced (reduction is gaining electrons). Therefore it reduces the 2br-, so (SO4)-2 is the reducing agent
In the reaction Ca + Br2 → CaBr2, calcium acts as the reducing agent because it undergoes oxidation by losing electrons to bromine. This results in the formation of calcium bromide (CaBr2).
2 NaBr (aq) + Cl2 (g) → 2 NaCl (aq) + Br2 (aq) Oxidation reduction reaction 2 Br-I - 2 e- → 2 Br0 (oxidation) 2 Cl0 + 2 e- → 2 Cl-I (reduction) NaBr is a reducing agent, Cl2 is an oxidizing agent.
Bromine is the oxidizing element.
Do you meann Br2? there is no B2 diboron species as far as I know. Br2 has a bondl length of 228 pm
NaCl is ionically bonded with stong electrostatic attractions whereas Cl2 only has weak Van Der Waals' forces acting between the molecules More strength is needed to break NaCl's bonds than CL2's bonds. Therefore, NaCl is solid and Cl2 is a gas Hope this helps :)
bromine water means the liquid formed by dissolving bromine in water. Br2.H2O From M.Swamy
HCL has a higher boiling point compared to HBr This is due to difference in electronegativity. H - 2.1 Cl - 3.0 Br - 2.8 The difference for HCl is 0.9, the difference for HBr is 0.7. The larger the difference in electronegavity means the stronger the bond. Large difference means greater attraction hence more energy is needed to overcome this bond.
In this reaction, Br is the reducing agent because it is being oxidized from Br- to Br2, thereby causing the reduction of Ca from Ca to Ca2+.