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Does molal elevation constant depend on nature of solvent?

This is a colligative property which does not depend on the nature of solute is the molal boiling point elevation constant or ebullioscopic constant of the solvent.


What is the boiling point of a 2.0 molal solution of glucose?

The boiling point is 101 oC.


What is molal depression constant?

Molal depression constant (Kf) is a colligative property constant that relates the lowering of the freezing point of a solvent to the molality of a solute in the solution. It is specific to each solvent and typically expressed in units of °C kg/mol.


What is the freezing point depression constant for water?

The freezing point depression constant for water is 1.86 degrees Celsius per molal.


Does elevation of blood glucose elevate your temperature?

No, elevated blood glucose with have no effect on temperature.


Calculate the boiling point of a solution of 10 grams of sodium chloride in 200 grams of water?

The boiling point elevation is determined by the molality of the solution, which can be calculated as the moles of solute divided by the mass of solvent in kg. From there, you can use the van't Hoff factor and the molal boiling point elevation constant to determine the change in boiling point. For sodium chloride, the van't Hoff factor is 2. The boiling point elevation constant for water is approximately 0.51 degrees Celsius/m.


What is meant by constant molal overflow?

Constant molal overflow is a term used in binary distillation. When a 2 component mixture is being separated in a distillation column,the assumption of constant molal overflow means assuming that both components have the same enthalpy. It assumes that one mole of component 1 when it condenses will vapourise 1 mole of component 2,also assumes no heat loss from the column. Can be wildly innacurate,particularly with separating organic solvents,and water. Water has a uniquely high enthalpy,often 5-6 times higer than the organic solvents.


What does 1M glucose solution mean?

1M glucose means that 1 mole of glucose is dissolved in 1kg of water. Since 1M means 1 molal. And molality is equla to no.of moles of solute per kg of water.


How much would the boiling point of water increased if 4 mol of NaCl were added to 1 Kg of water?

4.08 degrees celcius


What is the experimentally determined concentration of particles for an 2.25 molal solution of an ionic substance in water if the boiling point of the solution is 100.3 oC?

The experimentally determined concentration of particles for a 2.25 molal solution can be calculated using the formula: ΔTb = i * Kf * molality, where ΔTb is the boiling point elevation, i is the Van't Hoff factor, Kf is the ebullioscopic constant for water (0.512 oC/kg/mol), and molality is 2.25 mol/kg. From the given values, you can solve for the Van't Hoff factor (i) to determine the concentration of particles in the solution.


How much would the freezing point decrease if a 3.23 molal solution were achieved?

The freezing point depression of a solution is given by the equation ΔTf = Kf * m, where ΔTf is the freezing point depression, Kf is the cryoscopic constant, and m is the molality of the solution. With the molality (m) of 3.23 molal and the cryoscopic constant for water (Kf) being approximately 1.86 ºC kg/mol, you can calculate the freezing point depression.


The molal freezing point constant kf is a property of the solvent not the solute What does this say about the fact that freezing point depends on the amount of solute rather than solute's nature?

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