1.45 g Cr x (1 mol Cr/52.0 g Cr) x (6.022x 1023 atoms Cr/1 mol Cr) = 1.68 x 1022 atoms
To find the number of moles of Cr in the sample, first calculate the molar mass of Cr (chromium). Chromium has an atomic mass of approximately 51.996 g/mol. Next, divide the number of atoms by Avogadro's number (6.022 x 10^23 atoms/mol) to convert atoms to moles. So, 4.37 x 10^23 atoms of Cr is equivalent to 0.725 moles of chromium.
Which sample contains the greatest number of atoms. A sample of Mn that contains 3.29E+24 atoms or a 5.18 mole sample of I?The sample of _____ contains the greatest number of atoms.Answer:In order to compare the two samples, it is necessary to express both quantities in the same units. Since the question was phrased in terms of atoms, it is convenient to convert moles of I to atoms of I.The conversion factor between atoms and moles is Avogadro's number: 6.02 x 1023 "things" / molTo convert 5.18 moles of I to atoms of I:atoms I= 5.18 mol I6.02 x 1023 atoms I = 3.12E+24 atoms I1 mol IMultiply by atoms per mole. Moles cancel out.The sample of Mn contains 3.29E+24 atoms.Since 3.12E+24 is smaller than 3.29E+24, the sample of Mn contains the greatest number of atoms.
Two Chromium Atoms, and 3 Oxygen Atoms. (Cr2O3)
A dichromate ion (Cr2O7^2-) contains a total of 9 atoms - 2 chromium (Cr) atoms and 7 oxygen (O) atoms.
This is some easy math: chromium (Cr, #24) has an atomic mass of 52 grams per mole (from the periodic table). According to the Avogadro constant, 1 mole of any substance contains 6.02x1023 representative particles. So, 52g of Cr is 1 mole, and contains 6.02x1023 atoms.
Take the actual sample weight of 13grams, and divide it by the atomic weight of chromium. This gives you your molar percentage of atoms. Now multiply this molar percentage by Avogadro's constant, the number of atoms in one mole, and this will give you your number of atoms in the sample.
To find the number of moles of Cr in the sample, first calculate the molar mass of Cr (chromium). Chromium has an atomic mass of approximately 51.996 g/mol. Next, divide the number of atoms by Avogadro's number (6.022 x 10^23 atoms/mol) to convert atoms to moles. So, 4.37 x 10^23 atoms of Cr is equivalent to 0.725 moles of chromium.
Which sample contains the greatest number of atoms. A sample of Mn that contains 3.29E+24 atoms or a 5.18 mole sample of I?The sample of _____ contains the greatest number of atoms.Answer:In order to compare the two samples, it is necessary to express both quantities in the same units. Since the question was phrased in terms of atoms, it is convenient to convert moles of I to atoms of I.The conversion factor between atoms and moles is Avogadro's number: 6.02 x 1023 "things" / molTo convert 5.18 moles of I to atoms of I:atoms I= 5.18 mol I6.02 x 1023 atoms I = 3.12E+24 atoms I1 mol IMultiply by atoms per mole. Moles cancel out.The sample of Mn contains 3.29E+24 atoms.Since 3.12E+24 is smaller than 3.29E+24, the sample of Mn contains the greatest number of atoms.
Which sample contains the greatest number of atoms. A sample of Al that contains 8.18E+23 atoms or a 5.16 mole sample of S?The sample of______ contains the greatest number of atoms.Answer:In order to compare the two samples, it is necessary to express both quantities in the same units. Since the question was phrased in terms of atoms, it is convenient to convert moles of S to atoms of S.The conversion factor between atoms and moles is Avogadro's number: 6.02 x 1023 "things" / molTo convert 5.16 moles of S to atoms of S:atoms S=5.16 mol S6.02 x 1023 atoms S= 3.11E+24 atoms S1 mol SMultiply by atoms per mole. Moles cancel out.The sample of Al contains 8.18E+23 atoms.Since 3.11E+24 is larger than 8.18E+23, the sample of S contains the greatest number of atoms.
Chromate is an anion which contains 4 atoms of oxygen, and 1 of Chromium
Two Chromium Atoms, and 3 Oxygen Atoms. (Cr2O3)
A dichromate ion (Cr2O7^2-) contains a total of 9 atoms - 2 chromium (Cr) atoms and 7 oxygen (O) atoms.
This is some easy math: chromium (Cr, #24) has an atomic mass of 52 grams per mole (from the periodic table). According to the Avogadro constant, 1 mole of any substance contains 6.02x1023 representative particles. So, 52g of Cr is 1 mole, and contains 6.02x1023 atoms.
This depends on the mass of the gold sample.
Chromium nitrate is an ionic compound. It is composed of chromium cations (Cr3+) and nitrate anions (NO3-), which are held together by ionic bonds due to the transfer of electrons from chromium to nitrate.
Chromium VI sulphate Cr(SO4)3
Cr2O3 is, Chromium (III) oxide or simply Chromium oxide.