A gram atomic mass of helium (He) contains the same number of atoms as 1 mole of helium. Since 1 mole of any substance contains approximately 6.022 x 10^23 atoms, a sample of helium with a gram atomic mass would contain that same number of atoms.
Not much! 2980 atoms sodium [1 mole Na/6.022 X 1023 (atoms)][22.99 grams/1 mole Na] = 1.138 X 10 -19 grams sodium ====================
The total number of atoms contained in a 1,00 mole sample of helium is 6,022 140 857.10e23.
The number of atoms is 1,50553521.10e23.
Each water molecule contains two hydrogen atoms. Therefore, the number of water molecules present in the sample can be calculated by dividing the number of hydrogen atoms by 2. In this case, 3.6 moles of hydrogen atoms corresponds to 1.8 moles of water molecules. This is equal to approximately 1.08 x 10^24 water molecules.
Which sample contains the greatest number of atoms. A sample of Mn that contains 3.29E+24 atoms or a 5.18 mole sample of I?The sample of _____ contains the greatest number of atoms.Answer:In order to compare the two samples, it is necessary to express both quantities in the same units. Since the question was phrased in terms of atoms, it is convenient to convert moles of I to atoms of I.The conversion factor between atoms and moles is Avogadro's number: 6.02 x 1023 "things" / molTo convert 5.18 moles of I to atoms of I:atoms I= 5.18 mol I6.02 x 1023 atoms I = 3.12E+24 atoms I1 mol IMultiply by atoms per mole. Moles cancel out.The sample of Mn contains 3.29E+24 atoms.Since 3.12E+24 is smaller than 3.29E+24, the sample of Mn contains the greatest number of atoms.
Which sample contains the greatest number of atoms. A sample of Al that contains 8.18E+23 atoms or a 5.16 mole sample of S?The sample of______ contains the greatest number of atoms.Answer:In order to compare the two samples, it is necessary to express both quantities in the same units. Since the question was phrased in terms of atoms, it is convenient to convert moles of S to atoms of S.The conversion factor between atoms and moles is Avogadro's number: 6.02 x 1023 "things" / molTo convert 5.16 moles of S to atoms of S:atoms S=5.16 mol S6.02 x 1023 atoms S= 3.11E+24 atoms S1 mol SMultiply by atoms per mole. Moles cancel out.The sample of Al contains 8.18E+23 atoms.Since 3.11E+24 is larger than 8.18E+23, the sample of S contains the greatest number of atoms.
This depends on the mass of the gold sample.
Whatever be the substance the one gram mole of that substance would have 6.023 x 1023 atoms or molecules or ions in it. Hence to get the mole just divide the number given by 6.023 x 1023
one mole of all substances contains 6.022 x 10^23 atoms =number of atoms in 22400 cm^3 of any gas at STP
A gram atomic mass of helium (He) contains the same number of atoms as 1 mole of helium. Since 1 mole of any substance contains approximately 6.022 x 10^23 atoms, a sample of helium with a gram atomic mass would contain that same number of atoms.
Not much! 2980 atoms sodium [1 mole Na/6.022 X 1023 (atoms)][22.99 grams/1 mole Na] = 1.138 X 10 -19 grams sodium ====================
A mole of any substance contains the same number of atoms, which is approximately 6.022 x 10^23. Therefore, a mole of silver atoms and a mole of gold atoms would both contain the same number of atoms.
The total number of atoms contained in a 1,00 mole sample of helium is 6,022 140 857.10e23.
The number of atoms is 1,50553521.10e23.
Each water molecule contains two hydrogen atoms. Therefore, the number of water molecules present in the sample can be calculated by dividing the number of hydrogen atoms by 2. In this case, 3.6 moles of hydrogen atoms corresponds to 1.8 moles of water molecules. This is equal to approximately 1.08 x 10^24 water molecules.
To find the number of hydrogen-1 atoms in a 1.007-g sample, first note that the molar mass of hydrogen-1 is approximately 1.007 g/mol. This means that 1.007 grams of hydrogen-1 corresponds to 1 mole of hydrogen atoms. Since one mole of any substance contains approximately (6.022 \times 10^{23}) atoms (Avogadro's number), a 1.007-g sample of hydrogen-1 contains about (6.022 \times 10^{23}) atoms.