Okay, let's define our terms here. By "salt" I assume you mean table salt, sodium chloride.
It doesn't really exist as "molecules" since it's ionic.
Complicating things even further, "starch" is a polymer/oligomer, and the size of its molecules varies considerably.
However, one formula unit of sodium chloride is much much smaller than even a small molecule of starch.
When iodine is added to a solution containing starch, it forms a starch-iodine complex in which the iodine molecules are trapped within the helical structure of the starch. This complex absorbs light differently than free iodine, resulting in a color change from yellow-brown (free iodine) to blue-black (starch-iodine complex).
Starch is added in iodometric titration as an indicator to detect the endpoint of the titration. In the presence of iodine, starch forms a blue complex that is easily visible. The appearance of this blue color signifies that all the iodine has reacted with the analyte, helping the person conducting the titration to know when the reaction is complete.
Iodine is not soluble in water because the intermolecular forces between iodine molecules (Van der Waals forces) are stronger than the forces between iodine and water molecules. This makes it difficult for iodine to break its solid lattice structure and separate into individual ions or molecules that can interact with water.
After 20 minutes, the glucose molecules will diffuse out of the bag through the partially permeable membrane because they are smaller in size than the starch molecules. The starch molecules, being too large to pass through the membrane, will remain inside the bag.
Because starch forms a dark blue colored soluble product with free iodine, so that the appearance of color in the solution from this reaction effectively shows when all the substances in the solution that react more strongly with iodine than does starch have been consumed and the titration is finished.
In other words this question asks if the pores are bigger or smaller than the iodine molecules. So.... the answer is that the iodine are smaller than the pores and the pores are bigger, because the iodine molecules need room to pass through, and the pores are not selectively permeable because they let the iodine through.
When iodine is added to a solution containing starch, it forms a starch-iodine complex in which the iodine molecules are trapped within the helical structure of the starch. This complex absorbs light differently than free iodine, resulting in a color change from yellow-brown (free iodine) to blue-black (starch-iodine complex).
1) water 2) IKI 3) Glucose 4) Membrane pores 5) starch obviously starch is larger than the pores b/c it is the only substance that didn't pass through the membrane. glucose is the most complex molecule out of the remaining three, (making it 3rd smallest) and IKI is even less complex, and water is the most simple.
No. Iodine molecules are much larger in a molecular scale. This is due to the number of shells (6 shells) that iodine possess, making it an extremely large element, and its existence as I2 in nature makes it even larger. Water is made up of 2 hydrogen atoms and 1 oxygen atom, making it relatively smaller in comparison.
Smaller
it is a yellowish/orange colour but when iodine is present, than it will turn an dark-blue/black colour
The starch solution will turn black, while the distilled water will remain brown, the same colour as the iodine. This is actually because water, normally used as a control, does not contain any starch and as we know, the iodine test is highly specific for the presence of starch hence no colour change other than iodine dissolving in water to form an iodine solution contrary to starch which we know complexes with iodine, to form starch-iodine complex forming the blue-black colour observed
The boiling point of iodine (184.3 0C) is substantially higher than the boiling point of chlorine (-34 0C). Each element occurs at standard temperature and pressure as diatomic molecules; iodine molecules have substantially more mass than chlorine molecules; dispersion forces will be higher beween iodine molecules as they have more electrons than chlorine molecules. Both these factors contribute, mass will alomost certainly be the predominant factor.
Starch is added in iodometric titration as an indicator to detect the endpoint of the titration. In the presence of iodine, starch forms a blue complex that is easily visible. The appearance of this blue color signifies that all the iodine has reacted with the analyte, helping the person conducting the titration to know when the reaction is complete.
Yes, starch molecules are generally larger than protein molecules. Starch is a polysaccharide made up of many glucose molecules linked together, while proteins are composed of amino acids linked in chains. This difference in molecular structure contributes to the varying sizes of the molecules.
when cultures are grown on starch plates (which are usually nutrient agar with starch added) gram's iodine can be used later to turn the plate blue. If there is a clear(not blue area) around the culture than it consumes starch. its used to help identify what you have cultured.
Iodine test forms a complex with both starch and glycogen, resulting in a color change. This complex is responsible for the blue color observed with starch. However, glycogen has a more branched structure than starch, causing a different interaction with iodine that leads to a red color instead of blue.