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Firstly, the moles of sufluric acid: n=? n=m/M
m=18g = (18)/(98.086)
M=98.086 =.18mol
Thefore, there is .18mol per 2 litre (18g in 2L)
Therefore, its molarity is .09mol/L

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To calculate the mass of H2SO4, you first find the moles of H2SO4 using the molarity formula (moles = molarity x volume). Then use the molar mass of H2SO4 (98.08 g/mol) to convert moles to grams. Given that the solution is 5.85 M, you would first calculate moles of H2SO4: 5.85 mol/L x 0.060 L = 0.351 mol. Then convert moles to grams: 0.351 mol x 98.08 g/mol ≈ 34.44 grams of H2SO4.


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Related Questions

What mass of H2SO4is contained in 60.00 mL of a 5.85 M solution of sulfuric acid?

To calculate the mass of H2SO4, you first find the moles of H2SO4 using the molarity formula (moles = molarity x volume). Then use the molar mass of H2SO4 (98.08 g/mol) to convert moles to grams. Given that the solution is 5.85 M, you would first calculate moles of H2SO4: 5.85 mol/L x 0.060 L = 0.351 mol. Then convert moles to grams: 0.351 mol x 98.08 g/mol ≈ 34.44 grams of H2SO4.


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