5 atoms in total: 1hydrogen, one nitrogen, and three oxygens
The number of millimoles of HNO3 present at the start of a titration will depend on the initial concentration and volume of the HNO3 solution. To calculate millimoles, you can multiply the concentration of HNO3 in moles per liter by the volume of the solution in liters.
To find the volume of 16M HNO3 required to react with 0.0214g of Cu metal, you need to calculate the moles of Cu. Then, using the balanced equation for the reaction between Cu and HNO3 (Cu + 4HNO3 → Cu(NO3)2 + 2NO2 + 2H2O), you can determine the moles of HNO3 needed. Finally, using the molarity of the HNO3 solution, you can calculate the volume in drops.
To determine the number of moles of HNO3 present in 450 g, we first need to calculate the molar mass of HNO3, which is approximately 63.01 g/mol. Next, we use the formula moles = mass/molar mass to find the number of moles. Therefore, 450 g of HNO3 is equal to 7.14 moles of HNO3.
[H=1,N=14,O=16] Gram molar weigt of HNO3=1+14+3x6 =15+48 =63g 1 mole ----------> 63 g 2.6 mole --------> 63x2.6 =163.8 g thus, 163.8g of HNO3 is present in 2.6 moles of compound
The chemical formula for nitric acid is HNO3.
No it does not have a charge.It is a molecule.
The number of millimoles of HNO3 present at the start of a titration will depend on the initial concentration and volume of the HNO3 solution. To calculate millimoles, you can multiply the concentration of HNO3 in moles per liter by the volume of the solution in liters.
To find the volume of 16M HNO3 required to react with 0.0214g of Cu metal, you need to calculate the moles of Cu. Then, using the balanced equation for the reaction between Cu and HNO3 (Cu + 4HNO3 → Cu(NO3)2 + 2NO2 + 2H2O), you can determine the moles of HNO3 needed. Finally, using the molarity of the HNO3 solution, you can calculate the volume in drops.
To determine the number of moles of HNO3 present in 450 g, we first need to calculate the molar mass of HNO3, which is approximately 63.01 g/mol. Next, we use the formula moles = mass/molar mass to find the number of moles. Therefore, 450 g of HNO3 is equal to 7.14 moles of HNO3.
2.14 x 10^(-3)
Molarity = moles of solute/Liters of solution ( get moles of HNO3 and 300 ml = 0.300 Liters ) 0.31 grams Nitric acid (1 mole HNO3/63.018 grams) = 0.004919 moles HNO3 Molarity = 0.004919 moles HNO3/0.300 Liters = 0.0164 M HNO3
The chemical formula for Hydrogen Nitrate is: HNO3
HNO3 is Nitric Acid
The chemical formula for nitric acid is HNO3.
The oxidation state of the nitrogen atom in HNO3 is +5. This is because oxygen is typically assigned an oxidation state of -2, and hydrogen is +1. In HNO3, the total oxidation states of the hydrogen and oxygen atoms sum to zero, leaving nitrogen with an oxidation state of +5 to balance the charge.
[H=1,N=14,O=16] Gram molar weigt of HNO3=1+14+3x6 =15+48 =63g 1 mole ----------> 63 g 2.6 mole --------> 63x2.6 =163.8 g thus, 163.8g of HNO3 is present in 2.6 moles of compound
To calculate the total number of atoms in 60g of HNO3, you need to convert the mass of HNO3 to moles using its molar mass. Then, you can use Avogadro's number (6.022 x 10^23 atoms/mol) to find the total number of atoms.