[H=1,N=14,O=16] Gram molar weigt of HNO3=1+14+3x6
=15+48
=63g
1 mole ----------> 63 g
2.6 mole --------> 63x2.6
=163.8 g
thus, 163.8g of HNO3 is present in 2.6 moles of compound
To neutralize the nitric acid, you need a 1:1 mole ratio of sodium hydroxide to nitric acid. First, calculate the moles of nitric acid in the solution using the formula Molarity = moles/volume. Then, use the mole ratio to find the moles of sodium hydroxide needed. Finally, convert this to grams using the molar mass of sodium hydroxide.
potassium dichromate- K2Cr2O7 12.5 grams K2Cr2O7 *(1 mol K2Cr2O7/294 grams K2Cr2O7)= .0425 mols K2Cr2O7 There's two mols of K (potassium) for every 1 mol of K2Cr2O7 (Potassium Dichromate) so you multiply the K2Cr2O7 by two to get mols of K .0425 mols K2Cr2O7*(2 mols K/1 mol K2Cr2O7)=.085 mols K Multiply by the molar mass of K to get grams .85 mols K*(39 grams/1 mol K)= 3.32 grams potassium
To find the number of moles in 18.0 grams of hydrogen gas, you need to divide the given mass by the molar mass of hydrogen gas. The molar mass of hydrogen gas (H2) is about 2.016 grams/mol. So, 18.0 grams / 2.016 grams/mol ≈ 8.93 moles of hydrogen gas.
Molarity = mols of solute/L of solution .1004 = mols of NaOH/.01864 moles of NaOH = .00187 Moles of NaOH = Moles of KHP Now, multiply .00187 by the molar mass of KHP .00187*204.22 = .38 g KHP
To find the number of moles in 4.50 grams of silver nitrate (AgNO3), you first need to calculate the molar mass of AgNO3. The molar mass of AgNO3 is 169.87 g/mol. Then, use the formula: moles = mass/molar mass. So, 4.50 grams of AgNO3 is equal to 0.0265 moles.
49.03924
603 grams of mercury are equivalent to 3,006 moles.
The mass is 0,324 g.
Mass percent = grams of solute/total grams of solution Mole fraction = mols component/total mols mix. Molarity = mols solute/L solution Molality = mols solute/kg solvent Hope this helps :)
To neutralize the nitric acid, you need a 1:1 mole ratio of sodium hydroxide to nitric acid. First, calculate the moles of nitric acid in the solution using the formula Molarity = moles/volume. Then, use the mole ratio to find the moles of sodium hydroxide needed. Finally, convert this to grams using the molar mass of sodium hydroxide.
The answer is 315,575 g.
potassium dichromate- K2Cr2O7 12.5 grams K2Cr2O7 *(1 mol K2Cr2O7/294 grams K2Cr2O7)= .0425 mols K2Cr2O7 There's two mols of K (potassium) for every 1 mol of K2Cr2O7 (Potassium Dichromate) so you multiply the K2Cr2O7 by two to get mols of K .0425 mols K2Cr2O7*(2 mols K/1 mol K2Cr2O7)=.085 mols K Multiply by the molar mass of K to get grams .85 mols K*(39 grams/1 mol K)= 3.32 grams potassium
You haven't listed a concentration or weight and what the compound is so moles cannot be worked out
To convert moles to grams, you need to use the molar mass of the compound. The molar mass of SO2 is approximately 64.07 g/mol. Multiplying the number of moles by the molar mass gives: 0.75 moles x 64.07 g/mol = 48.0525 grams of SO2.
There are 53.4 grams of F2 in 1.73 moles of F2. This is calculated using the molar mass of fluorine (F2) which is 37.9968 g/mol.
17.24 g Sr * 1 mol/87.62 g Sr = 0.1968 mols Sr
Multiply the moles given, by the atomic mass of chlorine and you have your answer. (3.55 Grams)