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[H=1,N=14,O=16] Gram molar weigt of HNO3=1+14+3x6

=15+48

=63g

1 mole ----------> 63 g

2.6 mole --------> 63x2.6

=163.8 g

thus, 163.8g of HNO3 is present in 2.6 moles of compound

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