Multiply the moles given, by the Atomic Mass of chlorine and you have your answer. (3.55 Grams)
To convert moles to grams, you need to use the molar mass of the compound. The molar mass of SO2 is approximately 64.07 g/mol. Multiplying the number of moles by the molar mass gives: 0.75 moles x 64.07 g/mol = 48.0525 grams of SO2.
To find the mass of 1.36 mol of carbon tetrafluoride (CF4), you need to multiply the molar mass of CF4 by the number of moles given. The molar mass of CF4 is approximately 88.004 g/mol. Therefore, the mass of 1.36 mol of CF4 would be 119.684 g.
If the reaction had a 75% yield, 75% of the theoretical maximum amount of NO2 molecules would be produced. To calculate the number of NO2 molecules formed, you would multiply the theoretical maximum by 0.75.
To solve this first the molar mass of Mg is needed (look at a periodic table). (Mg=23.0g/mol) Then convert the mols to grams as follows: (3.65 mol Mg) x (23.0 g/mol Mg) = 84.0 g Mg The mol units cancel in the conversion leaving only the gram units and the ammount in grams.
molar mass of sodium = 23 number of mols = mass/ molar mass therefore 46g of Na = 2 mol
49.03924
603 grams of mercury are equivalent to 3,006 moles.
The mass is 0,324 g.
Mass percent = grams of solute/total grams of solution Mole fraction = mols component/total mols mix. Molarity = mols solute/L solution Molality = mols solute/kg solvent Hope this helps :)
The answer is 315,575 g.
potassium dichromate- K2Cr2O7 12.5 grams K2Cr2O7 *(1 mol K2Cr2O7/294 grams K2Cr2O7)= .0425 mols K2Cr2O7 There's two mols of K (potassium) for every 1 mol of K2Cr2O7 (Potassium Dichromate) so you multiply the K2Cr2O7 by two to get mols of K .0425 mols K2Cr2O7*(2 mols K/1 mol K2Cr2O7)=.085 mols K Multiply by the molar mass of K to get grams .85 mols K*(39 grams/1 mol K)= 3.32 grams potassium
There are 53.4 grams of F2 in 1.73 moles of F2. This is calculated using the molar mass of fluorine (F2) which is 37.9968 g/mol.
17.24 g Sr * 1 mol/87.62 g Sr = 0.1968 mols Sr
To find the number of moles in 18.0 grams of hydrogen gas, you need to divide the given mass by the molar mass of hydrogen gas. The molar mass of hydrogen gas (H2) is about 2.016 grams/mol. So, 18.0 grams / 2.016 grams/mol ≈ 8.93 moles of hydrogen gas.
1 mol of oxygen is 16.00g. Therefore 2.43g of oxygen would contain 0.152 mols of oxygen. (2.43g/16.00g)
you would get 6.4 mols of NaCl and 0.3 mols of unreacted Na
The answer is 9,92 moles.