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Calculate the boiling point of a solution of 10 grams of sodium chloride in 200 grams of water?
The boiling point elevation is determined by the molality of the solution, which can be calculated as the moles of solute divided by the mass of solvent in kg. From there, you can use the van't Hoff factor and the molal boiling point elevation constant to determine the change in boiling point. For sodium chloride, the van't Hoff factor is 2. The boiling point elevation constant for water is approximately 0.51 degrees Celsius/m.
What is the boiling point of a solution of 72.4 grams of glycerol dissolved in 122.5 grams of water?
First find the molality--convert the 72.4 grams into mols; convert the grams of water into kilograms. Divide the mols by the Kg, which gives you 6.419m.No need to find the mol ions since it's a molecular compound.The molar boiling point constant for water is 0.51.Therefore:Tb=0.51(6.419)Tb=3.27since this is the boiling point elevation and we're trying to discover the new boiling point, add this number to 100 (the average boiling point of water)the final answer is 103.27o c
How is stoichiometry used to calculate energy absorbed when a mass liquid boils?
Grams liquid × mol/g × Hvap
How much energy is needed to melt 4.24 grams of Pd?
The energy required to melt a substance can be calculated using the heat of fusion value for that substance. The heat of fusion for palladium (Pd) is 16.74 kJ/mol. To convert grams to moles, divide the given mass by the molar mass of Pd (106.42 g/mol), then multiply by the heat of fusion value to find the energy needed to melt 4.24 grams of Pd.
How much liquid is in 100 grams?
The amount of liquid in 100 grams will vary depending on the density of the liquid. The volume of the liquid can be calculated by dividing the mass (100 grams) by the density of the liquid.
How much energy is released when 2 grams of water?
When 2 grams of water is converted from liquid to gas at its boiling point, it requires an input of approximately 2260 joules of energy. Conversely, when 2 grams of steam condenses into liquid water, it releases around 2260 joules of energy.
How much CO2 will be produced by boiling a kettle each time?
Boiling a kettle typically releases around 0.15 kg (150 grams) of CO2 into the atmosphere each time, mostly from the energy it consumes during the boiling process.
What is the total mass energy of 200 grams of carbon?
The total mass energy of 200 grams of carbon can be calculated using Einstein's famous equation E=mc^2. The mass energy is approximately 1.8 x 10^15 Joules.
Calculate the boiling point of a solution of 10 grams of sodium chloride in 200 grams of water?
The boiling point elevation is determined by the molality of the solution, which can be calculated as the moles of solute divided by the mass of solvent in kg. From there, you can use the van't Hoff factor and the molal boiling point elevation constant to determine the change in boiling point. For sodium chloride, the van't Hoff factor is 2. The boiling point elevation constant for water is approximately 0.51 degrees Celsius/m.
What is the boiling point of a solution of 72.4 grams of glycerol dissolved in 122.5 grams of water?
First find the molality--convert the 72.4 grams into mols; convert the grams of water into kilograms. Divide the mols by the Kg, which gives you 6.419m.No need to find the mol ions since it's a molecular compound.The molar boiling point constant for water is 0.51.Therefore:Tb=0.51(6.419)Tb=3.27since this is the boiling point elevation and we're trying to discover the new boiling point, add this number to 100 (the average boiling point of water)the final answer is 103.27o c
How much energy is involved in the formation of 5 grams of rust?
The energy involved in the formation of 5 grams of rust can be calculated using the enthalpy of formation of iron(III) oxide (rust), which is -824 kJ/mol. First, convert the mass of rust to moles, then use the molar enthalpy of formation to calculate the energy involved.
How much heat energy is produced when 22 grams of propane is burned in a stove?
To determine the heat energy produced when burning propane, we need to know its heat of combustion, which is approximately 50 MJ/kg. For 22 grams (0.022 kg) of propane, the energy released can be calculated as follows: 0.022 kg × 50,000 kJ/kg = 1,100 kJ. Therefore, burning 22 grams of propane produces about 1,100 kJ of heat energy.
Does it take more heat to vaporize 12 grams of CH4 or 12 grams of Hg?
It takes more heat to vaporize 12 grams of CH4 (methane) compared to 12 grams of Hg (mercury) because methane has weaker intermolecular forces and a lower boiling point. This means more energy is required to break the bonds between methane molecules to allow them to vaporize. Mercury has stronger intermolecular forces, so it requires less energy to vaporize.
How is stoichiometry used to calculate energy absorbed when a mass liquid boils?
Grams liquid × mol/g × Hvap
How does the temperature of 33 grams of graphite change when it absorbs 350 joules of thermal energy?
The temperature of graphite will increase because it absorbs thermal energy. The temperature increase can be calculated using the specific heat capacity of graphite.
How much energy is needed to melt 4.24 grams of Pd?
The energy required to melt a substance can be calculated using the heat of fusion value for that substance. The heat of fusion for palladium (Pd) is 16.74 kJ/mol. To convert grams to moles, divide the given mass by the molar mass of Pd (106.42 g/mol), then multiply by the heat of fusion value to find the energy needed to melt 4.24 grams of Pd.
What is the boiling point of a solution that contains 170g of sugar in 100 grams of water?
The boiling point of a solution can be calculated using the formula: ΔTb = i * Kf * m, where i is the van't Hoff factor, Kf is the ebullioscopic constant of the solvent, m is the molality of the solution in mol/kg, and ΔTb is the boiling point elevation. In this case, we would need additional information such as the van't Hoff factor of the sugar and the ebullioscopic constant of water to calculate the boiling point elevation accurately.
