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Calculated the energy to heat 32 grams of liqiud water from 47c to boiling?

Updated: 8/11/2023

Wiki User

15y ago

Q = mc (delta T) = 32.5 x 1 x (75-34) = 1332.5 cal

Wiki User

10y ago

Ethan10 Baller

Lvl 1
2y ago
Shouldn't the one be 4.18 because that is the amount of heat energy it requires to raise the temp. Right?

Wiki User

15y ago

boiling =100c so need to heat by 100-47 = 53 degrees 53*32 =1696 calories

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Q: Calculated the energy to heat 32 grams of liqiud water from 47c to boiling?
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