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[185/79] Au ==> [181/77]Ir + [4/2]He
These figures are fictitious, however, the [4/2]He is the helium nucleus,( alpha particle) which would be emitted.
What else can I help you with?
When bismuth-212 undergoes alpha decay, what does it become?
When bismuth-212 undergoes alpha decay, it becomes thallium-208.
What is the alpha decay of calcium 42 equation?
There is no equation. Calcium-42 is stable and does not decay. Calcium is also much to light for alpha decay, which requires elements heavier than nickel, so no isotope of calcium undergoes alpha decay.
How do you write a balanced nuclear equation for the formation of polonium-206 through alpha decay?
If radon-210 undergoes alpha decay, it will produce the alpha particle (which is a helium-4 nucleus) and polonium-206. The equation looks like this: 86210Ra => 24He + 84206Po You'll note that in the balanced nuclear equation, the atomic numbers, which are the subscripts, balance on both sides of the equation (86 = 2 + 84). The atomic masses, which are the superscripts, also balance on both sides of the equation (210 = 4 + 206).
What is the nuclear equation of the decay of uranium 238?
A:Uranium - 238 --> Pb - 206 + Alpha + Beta note this is a simplified over all reaction, the actual process involves around 15 steps...A:The equation for the alpha decay of 238U is: 92238U --> 90234Th + 24HeThe alpha particle is represented as an He nucleus.
What is the nuclear equation for the alpha decay of 242 Pu?
The nuclear equation for the alpha decay of 242Pu is: ^24294Pu -> ^23892U + ^4He2 This equation shows that the nucleus of 242Pu decays into a nucleus of 238U and an alpha particle, which is a helium-4 nucleus.
What would the balanced equation for the alpha decay of thorium 229 be?
The balanced equation for the alpha decay of thorium-229, Th-229, is: Th-229 -> Ra-225 + He-4 This equation shows that a thorium-229 nucleus undergoes alpha decay to form a radium-225 nucleus and a helium-4 particle.
How does uranium turn into thorium in equation form?
The reaction is:U-238(alpha)Th-234
When radon undergoes natural transmutation reaction it emits?
When radon undergoes natural transmutation, it emits alpha particles or alpha radiation. This process occurs as radon changes into a series of other radioactive elements before reaching a stable state. The alpha particles emitted during these decay processes can pose health risks if inhaled or ingested.
What is the balanced nuclear equation for the alpha for radium-226?
When radium-226 undergoes alpha decay, it becomes radon-222. We write the equation like this: 88226Ra => 24He + 86222Rn Here we see the alpha particle written as a helium-4 nucleus, which is, in point of fact, what it is. Notice that the numbers that are subscripted are equal on both sides of the equation, and the superscripted numbers are as well. They must balance for your equation to be correct.
When bismuth-212 undergoes alpha decay, what does it become?
When bismuth-212 undergoes alpha decay, it becomes thallium-208.
What is the alpha decay of calcium 42 equation?
There is no equation. Calcium-42 is stable and does not decay. Calcium is also much to light for alpha decay, which requires elements heavier than nickel, so no isotope of calcium undergoes alpha decay.
How do you write a balanced nuclear equation for the formation of polonium-206 through alpha decay?
If radon-210 undergoes alpha decay, it will produce the alpha particle (which is a helium-4 nucleus) and polonium-206. The equation looks like this: 86210Ra => 24He + 84206Po You'll note that in the balanced nuclear equation, the atomic numbers, which are the subscripts, balance on both sides of the equation (86 = 2 + 84). The atomic masses, which are the superscripts, also balance on both sides of the equation (210 = 4 + 206).
What is The Balanced Nuclear Equations For The Alpha Decay Of Radium-226?
When radium-226 undergoes alpha decay, it becomes radon-222. We write the equation like this: 88226Ra => 24He + 86222Rn Here we see the alpha particle written as a helium-4 nucleus, which is, in point of fact, what it is. Notice that the numbers that are subscripted are equal on both sides of the equation, and the superscripted numbers are as well. They must balance for your equation to be correct.
If seaborgium undergoes alpha decay which element is created?
If seaborgium undergoes alpha decay, it would create rutherfordium as the resulting element.
What is the nuclear decay equation for an example of alpha decay?
There are a number of radioactive isotopes of copper, choosing 66Cu as on that undergoes negative beta decay, the equation is: 2966Cu --> 3066Zn + -10e Where e represents the beta particle, which can also be viewed as an electron.
What is the nuclear equation of the decay of uranium 238?
A:Uranium - 238 --> Pb - 206 + Alpha + Beta note this is a simplified over all reaction, the actual process involves around 15 steps...A:The equation for the alpha decay of 238U is: 92238U --> 90234Th + 24HeThe alpha particle is represented as an He nucleus.
What is the nuclear equation for the decay of Po210 if it undergoes 2 alpha decay then a beta decay followed by another alpha decay.?
The nuclear equation for the decay of Po-210 undergoing 2 alpha decays followed by a beta decay and another alpha decay is: Po-210 -> Pb-206 + 4 He-4 + 2 e-1 + 2 v This equation represents the series of decays that result in the transformation of Po-210 into Pb-206, with the emission of two helium nuclei (alpha particles), two electrons, and two neutrinos.
