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To determine the value of i in freezing point depression, you can use the formula Tf i Kf m, where Tf is the freezing point depression, Kf is the cryoscopic constant, and m is the molality of the solute. By rearranging the formula and plugging in the known values, you can solve for i. The value of i represents the number of particles the solute breaks into in the solution.
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Describe the Beckmann's method for determining freezing point of so?
The Beckmann method involves adding a known mass of a solute to the solvent, measuring the freezing point depression caused by the solute, and using this data to calculate the molecular weight of the solute. By comparing the observed freezing point depression with the expected value, the true freezing point of the solvent can be accurately determined.
What is 21.6g NiSO4 in 1.00 102g H2O assume 100 percent ionization compute the freezing point of this solution?
To determine the freezing point depression of the solution, you first need to calculate the molality of the nickel sulfate (NiSO4) solution. Next, using the molality value and the cryoscopic constant of water, you can calculate the freezing point depression of the solution using the formula: ΔTf = Kf * m, where ΔTf is the freezing point depression, Kf is the cryoscopic constant of water (1.86°C/kg), and m is the molality of the solution.
How do you calculate freezing point of lacrymal fluid?
The freezing point of lacrimal fluid, which is mostly composed of water, can be calculated using the same formula used for calculating the freezing point of a solution. The formula is: ΔTf = i * Kf * m, where ΔTf is the freezing point depression, i is the van't Hoff factor, Kf is the cryoscopic constant, and m is the molality of the solution. Lacrimal fluid has an average osmolarity of around 300 mOsm/kg, so you can estimate the freezing point based on this value.
What is the freezing point of an aqueous 2.65 m calcium chloride solution?
dT = (i)(Kf)(m) is the equation that can be used to model the freezing point depression. dT represents the change change in temperature. i represents the amount of ions formed from the dissolution of the solute. Kf represents the constant of the freezing point depression of water. m is the molality of the solute in solution. dT = (3)(1.86 degC/m)(2.65m) dT = 14.8 degC 0-14.8 degC = -14.8 degC So the freezing point is -14.8 degrees C. The reason why this value was subtracted from zero is because the presence of a solute lowers the freezing point.
How can the Kf value of a solvent can be determined?
The Kf value of a solvent can be determined experimentally by measuring its freezing point depression when a known amount of solute is added. The formula used is ΔTf = Kf * m, where ΔTf is the depression in freezing point, Kf is the cryoscopic constant for the solvent, and m is the molality of the solution. By rearranging this formula, Kf can be calculated by Kf = ΔTf / m.
Describe the Beckmann's method for determining freezing point of so?
The Beckmann method involves adding a known mass of a solute to the solvent, measuring the freezing point depression caused by the solute, and using this data to calculate the molecular weight of the solute. By comparing the observed freezing point depression with the expected value, the true freezing point of the solvent can be accurately determined.
What is 21.6g NiSO4 in 1.00 102g H2O assume 100 percent ionization compute the freezing point of this solution?
To determine the freezing point depression of the solution, you first need to calculate the molality of the nickel sulfate (NiSO4) solution. Next, using the molality value and the cryoscopic constant of water, you can calculate the freezing point depression of the solution using the formula: ΔTf = Kf * m, where ΔTf is the freezing point depression, Kf is the cryoscopic constant of water (1.86°C/kg), and m is the molality of the solution.
What would the final freezing point of water be if 3 mol of sugar were added to 1 kg of water?
-5.58 C
How do you calculate freezing point of lacrymal fluid?
The freezing point of lacrimal fluid, which is mostly composed of water, can be calculated using the same formula used for calculating the freezing point of a solution. The formula is: ΔTf = i * Kf * m, where ΔTf is the freezing point depression, i is the van't Hoff factor, Kf is the cryoscopic constant, and m is the molality of the solution. Lacrimal fluid has an average osmolarity of around 300 mOsm/kg, so you can estimate the freezing point based on this value.
What is the freezing point of an aqueous 2.65 m calcium chloride solution?
dT = (i)(Kf)(m) is the equation that can be used to model the freezing point depression. dT represents the change change in temperature. i represents the amount of ions formed from the dissolution of the solute. Kf represents the constant of the freezing point depression of water. m is the molality of the solute in solution. dT = (3)(1.86 degC/m)(2.65m) dT = 14.8 degC 0-14.8 degC = -14.8 degC So the freezing point is -14.8 degrees C. The reason why this value was subtracted from zero is because the presence of a solute lowers the freezing point.
What is the solution's freezing point depression?
To solve freezing point depression problems, you need to know the following things:-- the identity of the solute (the thing you are adding to the liquid)-- the identity of the solvent (the liquid)-- whether the solute is molecular or ionic, and if ionic, how many ions it forms-- the amount of solute (in grams or moles)-- the amount of solvent (in kilograms)-- the value of Kf of the solvent (for water, it is -1.858 K·kg/mol (or -1.858 °C molal-1)Then you use the following equation:∆T = i * Kf * mwhere ∆T is the change in the freezing point, "i" is the number of molecules or ions formed upon addition to the solvent, Kf is the freezing point depression constant, and "m" is the molality of the solution.The Kf of water for a freezing point depression is known and is equal to -1.858 °C·kg/mol (or -1.858 °C molal-1)The value of "i" has to do with what you add to the water. If you added sugar, a molecular compound the value of "i" is 1.0. If you add a ionic compound like NaCl, the value of "i" is 2.0 because for every 1 molecule of NaCl, you make 2 ions: one Na+ and one Cl- in water. For MgCl2, the value of "i" is thus 3.0 (for each MgCl2 you get one Mg2+ and two Cl- ions, so a total of 3 ions).To find "m," the molality of a solution you need to know the number of moles of solute and the number of kilograms of solvent (m = moles/kg). If you are given the number of grams of solute, the number of moles is found from the mass and the molar mass of the solute.grams of solute ÷ molar mass of solute = moles of soluteTo find the molality, just divide the moles of solute by the kilograms of solvent moles of solute ÷ kilograms solvent = molality Note: If you are given the volume of the solvent instead of the mass, use the density of the solvent to convert -- the density of water is 1 kilogram per liter)Liters of solvent * density of solvent = kilograms of solventNow just plug all the numbers into the equation at the top of the answer!
How can the Kf value of a solvent can be determined?
The Kf value of a solvent can be determined experimentally by measuring its freezing point depression when a known amount of solute is added. The formula used is ΔTf = Kf * m, where ΔTf is the depression in freezing point, Kf is the cryoscopic constant for the solvent, and m is the molality of the solution. By rearranging this formula, Kf can be calculated by Kf = ΔTf / m.
What do melting melting point and freezing point have in common?
They have an equal value and are synonyms.
Liquid to solid temp?
This temperature is called freezing point (the value is equivalent to the melting point).
How can one determine the initial value on a graph?
To determine the initial value on a graph, look for the point where the graph intersects the y-axis. This point represents the initial value or starting point of the graph.
What temp does liquid change into solid?
This temperature is called freezing point (the value is equivalent to the melting point).
What is the freezing point of nobelium?
An estimated value is 827 0C.
