This depends on the mass of NaOH dissolved in 1 L water.
titration
(100ml)(0.125M NaOH) = (500ml)(X Molarity) Molarity = 0.025 M
I assume you mean 32.0 grams of NaOH and 450 milliliters of NaOH. Molarity = moles of solute/Liters of solution ( 450 ml = 0.450 liters ) get moles of NaOH 32.0 grams NaOH (1 mole NaOH/39.998 grams) = 0.800 moles NaOH Molarity = 0.800 moles NaOH/0.450 liters = 1.78 Molar NaOH
The answer is 0,625 moles.
Molarity = moles of solute/Liters of solution 3.42 M NaOH = 1.3 moles NaOH/Liters NaOH Liters NaOH = 1.3 moles NaOH/3.42 M NaOH = 0.38 Liters
Moles/Liters=Molarity (M) therefore: Molarity*Liters=moles Since you were given milliliters, you must first convert your volume to liters for the equation to be accurate. 2.2M*.065L=moles=.143 moles NaOH
15g in 100L is 0.15g/ litre. The molecular weight of NaOH is 40g/mol. 0.15/40 is .00375 molar.
(100ml)(0.125M NaOH) = (500ml)(X Molarity) Molarity = 0.025 M
I assume you mean 32.0 grams of NaOH and 450 milliliters of NaOH. Molarity = moles of solute/Liters of solution ( 450 ml = 0.450 liters ) get moles of NaOH 32.0 grams NaOH (1 mole NaOH/39.998 grams) = 0.800 moles NaOH Molarity = 0.800 moles NaOH/0.450 liters = 1.78 Molar NaOH
80g of NaOH dissolved in 250ml. of water find the molarity of this solution ?
1620 ml = 1.62 Liters Molarity = moles of solute/Liters of solution Molarity = 2 moles NaOH/1.62 Liters = 1 M NaOH solution ===============
95g NaOH * 1 mol NaOH/ = 2.375 mol NaOH 40g NaOH Molarity (M) = mol / L M = (2.375) / (0.450) M = 5.28
molarity equals moles of solute /volume of solution in litres . moles of NaOH equals 5g/40g = 0.125 and volume of solution will be volume of water + volume of NaOH = 0.5 litre+0.002 l which is nearly 0.5 litre . (volume of NaOH is calculated by its density) so molarity = 0.125mol/0.5litre = 0.25 M
The answer is 0,625 moles.
The molarity is 0,33.
The molarity is 0,2.
This sodium hydroxide solution has a molarity of 0,25.
The molarity is 0,031.