NaOH + CH3OH --> CH3ONa + H2O
Evaporate the solution to dryness, add more CH3OH and evaporate to dryness.
you can repeat a few times to ensure the remaining solid is sodium methoxide
When sodium hydroxide reacts with methanol, a neutralization reaction occurs, forming sodium methoxide and water. The balanced chemical equation for this reaction is: CH3OH + NaOH → CH3ONa + H2O
The reaction between 2-iodohexane and sodium methoxide will result in an SN2 substitution reaction. The equation can be represented as: 2-iodohexane + Sodium methoxide → Hexane + Sodium iodide + Methanol
No. Magnesium methoxide will react with water to form a gel. The gel is actually a cross-linked Magnesium hydroxide structure in methanol. Magnesium methoxide is typically sold/stored in dry methanol to protect the chemical as it is incredibly hygroscopic.
You can separate acetic acid from zinc methoxide by adding water, which will hydrolyze zinc methoxide to form zinc hydroxide and methanol. Acetic acid is not affected by this reaction and will remain in the solution. The zinc hydroxide can then be filtered out, leaving behind the acetic acid solution.
The reaction of methanol with sodamide (NaNH2) typically results in the formation of sodium methoxide (NaOCH3) and ammonia (NH3) as byproducts. This reaction is often used for the synthesis of sodium alkoxides.
The sodium methoxide reacts with the water to produce sodium hydroxide an methanol.
No. Alkoxide ions are stronger bases than hydroxide ions. The only way of making an alkoxide is by reacting a hihgly reactive metal such as sodium with the corresponding alcohol (react sodium with methanol to produce sodium methoxide). In water sodium methoxide will react to produce sodium hydroxide and methanol.
When sodium methoxide is added to water, it will undergo hydrolysis, producing sodium hydroxide and methanol. This reaction releases heat and sodium hydroxide is a strong base that can cause skin and eye irritation. Extreme care should be taken when handling sodium methoxide as it is highly reactive.
When sodium hydroxide reacts with methanol, a neutralization reaction occurs, forming sodium methoxide and water. The balanced chemical equation for this reaction is: CH3OH + NaOH → CH3ONa + H2O
sodium azide + methanol
The reaction between 2-iodohexane and sodium methoxide will result in an SN2 substitution reaction. The equation can be represented as: 2-iodohexane + Sodium methoxide → Hexane + Sodium iodide + Methanol
Firstly, sodium methoxide is extremely toxic, so you want to handle it carefully without ever spilling (e.g. from an unsealed container). Secondly, methanol is hygroscopic and will pick up lots of water from the atmosphere. Water will hydrolyze sodium methoxide into methanol and sodium hydroxide. You wouldn't want your methanol to evaporate either.
No. Magnesium methoxide will react with water to form a gel. The gel is actually a cross-linked Magnesium hydroxide structure in methanol. Magnesium methoxide is typically sold/stored in dry methanol to protect the chemical as it is incredibly hygroscopic.
You can separate acetic acid from zinc methoxide by adding water, which will hydrolyze zinc methoxide to form zinc hydroxide and methanol. Acetic acid is not affected by this reaction and will remain in the solution. The zinc hydroxide can then be filtered out, leaving behind the acetic acid solution.
The reaction of methanol with sodamide (NaNH2) typically results in the formation of sodium methoxide (NaOCH3) and ammonia (NH3) as byproducts. This reaction is often used for the synthesis of sodium alkoxides.
One possible product of the reaction between chloromethane and sodium hydroxide solution is methanol and sodium chloride. Methanol is formed by the substitution of the chlorine in chloromethane with the hydroxide ion from sodium hydroxide, while sodium chloride is a byproduct of the reaction.
The mechanism of the sodium borohydride reaction with methanol involves the transfer of a hydride ion from sodium borohydride to methanol, resulting in the formation of sodium methoxide and hydrogen gas. This reaction is a nucleophilic addition-elimination process, where the hydride ion acts as a nucleophile attacking the electrophilic carbon in methanol.